Question

Solve for x in sin xtan x + tan x – 2sin x + cos x = 0 for 0 ≤ x ≤2π rads.

Answer 1

The value of x = 4.71, 0.41, or 5.89 radian value

Specification:

sinxtanx + tanx -2sinx + cosx = 0

tanx = sinx / cosx

sinx (sinx / cosx) + sinx / cosx -2sinx + cosx = Multiply 0

cosx to remove the fraction

sin ^ 2 (x) + sinx -2sinxcosx + cos ^ 2 (x) = 0

sin ^ 2 (x) + cos ^ Replace with 1. 2 (x) = 1

sinx -2sinxcosx + 1 = 0

sinx (1-2cosx) = -1

1-2cosx = -1 / sinx

-2cosx = -1 / sinx -1

2cosx = 1 / sinx + 1

cosx = 1 / 2sinx + 1/2

sqr (1-sin ^ 2 (x)) = 1 / 2sinx + 1/2

Squared on both sides

1-sin ^ 2 (x) = 1 / 4sin ^ 2 (x) + 1 / 2sinx + 1/4

4sin ^ 2 (x) Multiply

4sin ^ 2 (x) -4sin ^ 4 (x) = 1 + 2sinx + sin ^ 2 (X)

4sin ^ 4 (x) -3sin ^ 2 (x) + 2sinx +1 = 0

y = sinx

4y ^ 4 -3y ^ 2 + 2y + 1 = 0

sinx = y = -1 or -0.3478

x = 270, 180-22.61 or -22.61 degrees

x = 270, 157.39 or 337 .39 degrees

or

x = 3pi / 2, 0.13pi or 1.87pi radians

or

x = 4.71, 0.41 Or 5.89 radians

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