6v+4w-4
Because you do -*-6v=positive 6v then -*-4w=positive 4w and then -*4=-4 and that takes care of the parenthesis
Basically you multiply the outside number or sign by all things inside the parenthesis
So in this problem you multiplied the negative sign by all the things inside the parenthesis
Answer:
10
Step-by-step explanation:
Begin with writing down your problem. For example, you want to divide 1284 by 14.
Decide on which of the numbers is the dividend, and which is the divisor. The dividend is the number that the operation is performed on - in this case, 1284. The divisor is the number that actually "does the work" - in this case, 14.
Perform the division - you can use any calculator you want. You will get a result that most probably is not an integer - in this example, 91.7142857.
Round this number down. In our example, you will get 92.
Multiply the number you obtained in the previous step by the divisor. In our case, 92 * 14 = 1294.
Subtract the number from the previous step from your dividend to get the remainder. 1284 - 1294 = 10.
Answer: The explicit rule for the geometric sequence is:
an=15 (1/5)^(n-1), for n=1, 2, 3, 4, ...
Solution:
Sequence:
15, 3, 3/5, 3/25
a1=15
a2=3
a3=3/5
a4=3/25
a2/a1=3/15=(3/3)/(15/3)→a2/a1=1/5
a3/a2=(3/5)/3=(3/5)/(3/1)=(3/5)/(1/3)→a3/a2=1/5
a4/a3=(3/25)/(3/5)=(3/25)(5/3)=5/25=(5/5)/(25/5)→a4/a3=1/5
(an)/(an-1)=(1/5)
Solving for an:
an=(1/5) (an-1)
a1=15
n=2→a2=(1/5)(a2-1)=(1/5)(a1)=(1/5)(15)→a2=15 (1/5)
n=3→a3=(1/5)(a3-1)=(1/5)(a2)=(1/5)[(15) (1/5)]=15 (1/5)^(1+1)→
a3=15 (1/5)^2
n=4→a4=(1/5)(a4-1)=(1/5)(a3)=(1/5)[15 (1/5)^2]=15 (1/5)^(2+1)→
a4=15 (1/5)^3
a1=15→a1=15 (1/5)^0=15 (1/5)^(1-1)
a2=15 (1/5)→a2=15 (1/5)^1=15 (1/5)^(2-1)
a3=15 (1/5)^2=15 (1/5)^(3-1)
a4=15 (1/5)^3=15 (1/5)^(4-1)
Then:
an=15 (1/5)^(n-1), for n=1, 2, 3, 4, ...
Answer: Hello the options related to your question is missing attached below are the missing options.
A.) The probabilities of the RVs may be equal
B.) The sum of the probabilities of the RVs exceed 1
C.) This is an impossible occurrence
D.) The probabilities of the RVs must be equal
E.) None of the above
answer:
The probabilities of the RVs may be equal ( A )
Step-by-step explanation:
Given that the value of the population mean and the value of probability mass function of a set of random variables are similar
For the Random Variables : 100,200,300,400
The Probability mass function of RV = ( 100 + 200 + 300 + 400 ) / 4
Hence The probabilities of the RVs may be equal
Equivalents man atleast I think