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fiasKO [112]
2 years ago
13

Consider the quadratic function f(x) = x2 – 5x + 12. Which statements are true about the function and its graph? Select three op

tions. The value of f(–10) = 82 The graph of the function is a parabola. The graph of the function opens down. The graph contains the point (20, –8). The graph contains the point (0, 0).
Mathematics
1 answer:
klasskru [66]2 years ago
4 0

The graph of the quadratic function f(x)=x² - 5x + 12 is a parabola which opens up.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

The standard form of a quadratic equation is:

y = ax² + bx + c

The graph of a quadratic equation is a parabola.

The graph of the quadratic function f(x)=x² - 5x + 12 is a parabola which opens up.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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What -2x(2-6=30)^3 - 4
BlackZzzverrR [31]
I think the answer to 2×(2-6=30)×3-4 is 176
6 0
4 years ago
A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
yKpoI14uk [10]

The correct statement is:

  • There are four ways to choose the committee.
  • There are three ways to form the committee if person D must be on it.
  • If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

#SPJ4

<em>Your question is incomplete. Please read below to find the missing content.</em>

<em />

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0
2 years ago
Please help me. This is due today
sattari [20]

Answer:

it answer is 3 because it is trigonometry

3 0
3 years ago
What is the distance between the points plotted below? If necessary, round your answer to two decimal places.
34kurt
(-1,1) (6,9)
distance = root (x1-x2)²+(y1-y2)²
so root (-1-6)²+(1-9)²= root 113 or 10.6 ≈11
the answer is B. 11.18 units
8 0
3 years ago
Read 2 more answers
Find the value of x which ABCD must be a parallellogram?<br> x =
svetoff [14.1K]
ABCD\ is\ parallelogram\ then\ :\\\\\underbrace{15x+2=9x+20}_{alternate\ angles}\ \ \ |subtract\ 2\ from\ both\ sides\\\\15x=9x+18\ \ \ \ |subtract\ 9x\ from\ both\ sides\\\\6x=18\ \ \ \ |divide\ both\ sides\ by\ 6\\\\\boxed{x=3}
3 0
3 years ago
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