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andrew-mc [135]
2 years ago
6

Type the correct answer in each box. Use numerals instead of words.

Mathematics
1 answer:
N76 [4]2 years ago
3 0

The simplification of the polynomial expression will give 3x² - 20x + 8.

<h3>How to illustrate the polynomial?</h3>

The polynomial expression is given as:

(5x² + 13x4) (17x² + 7x - 19) + (5x-7)(3x + 1)

= 5x² + 13x - 4 - 17x² - 7x + 19 + 15x² + 5x - 21x - 7

Then collect like terms

= 5x² + 15x² - 17x² + (13x - 7x + 5x - 21x) - 4 - 7 + 19

= 3x² - 20x + 8.

Learn more about polynomial on:

brainly.com/question/2833285

#SPJ1

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How many pairs of parallel sides does a trapezoid have? none/ one/ three/ two
telo118 [61]
A trapezoid has two parallel sides, but the top one is shorter than the bottom one
3 0
3 years ago
What does x equal in 7+2/5x=-5
Anna007 [38]

Answer:

x = -30

Step-by-step explanation:

subtract 7 from both sides ( 7+2/5x -7, -5-7 )

simplify ( 2/5x = 12 )

multiply both sides by 5 ( 2/5x times 5 = 5 (-12) )

simplify ( 2x = -60 )

divide both sides by 2 ( 2x / 2, -60 / 2 )

x = -30

7 0
3 years ago
Read 2 more answers
A city council consists of seven Democrats and five Republicans. If a committee of four people is selected, find the probability
Hoochie [10]

Answer:

The probability  of selecting two Democrats and two Republicans is 0.4242.

Step-by-step explanation:

The information provided is as follows:

  • A city council consists of seven Democrats and five Republicans.
  • A committee of four people is selected.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

Compute the number of ways to select four people as follows:

{12\choose 4}=\frac{12!}{4!\times (12-4)!}=495

Compute the number of ways to selected two Democrats as follows:

{7\choose 2}=\frac{7!}{2!\times (7-2)!}=21

Compute the number of ways to selected two Republicans as follows:

{5\choose 2}=\frac{5!}{2!\times (5-2)!}=10

Then the probability  of selecting two Democrats and two Republicans as follows:

P(\text{2 Democrats and 2 Republicans})=\frac{21\times 10}{495}=0.4242

Thus, the probability  of selecting two Democrats and two Republicans is 0.4242.

6 0
2 years ago
Please help! marking brainliest :)
andreev551 [17]

Answer: 30

Step-by-step explanation:

rounding 34 to nerest numder 30 or 40

5 0
3 years ago
how many numbers are there that have distinct digits and are greater than 4500? how many 5 digit odd numbers are there that have
marusya05 [52]

Answer:

4-digit numbers with distinct digits and greater than 4500: 2800 numbers

5-digit numbers with distinct digits: 27216 numbers.

Step-by-step explanation:

If we represent a 4 number digit by ABCD, we have 9 posibilities for A (1,2,3,4,5,6,7,8 and 9, all but 0).

If every digit has to be different, we have 9 posibilities for B: ten digits (0,1,2,3,4,5,6,7,8 and 9 minus the one already used in A).

Int he same way, we have 8 posibilities for C and 7 for D.

Considering all 4-digits numbers, we have 9*9*8*7 = 4536 numers with distinct digits.

To know how many of these numbers are greater than 4500, we can substracte first the numbers that are smaller than 4000: A can take 3 digits (1,2 and 3) and B, C and D the same as before.

3*9*8*7 = 1512 numbers smaller than 4000

Then we can substrat the ones that are between 4000 and 4500

1*4*8*7 = 224 numbers between 4000 and 4500

So, if we substract from the total the numbers that are smaller than 4500 we have the results:

4-digit numbers with distinct digits greater than 4500 = 4536-(1512+224) = 2800

For 5-digit numbers, we can call the number ABCDE.

For A we have 9 digits possible (all but 0).

For B, we also have 9 posibilities (all digits but the one used in A).

For C, we have 8 digits (all 10 but the ones used in A and B).

For D, we have 7 digits.

For E, we have 6 digits.

Multiplying the possible combinations, we have:

9*9*8*7*6 =  27,216 5-digit numbers with distinct digits.

3 0
3 years ago
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