Question

(√x+1/√x)^2find dy/ dx and substitute 2 in dy/ dx

Answer 1

Hello,
That's better.

I suppose $y=( \sqrt{x} + \dfrac{1}{ \sqrt{x} } )^2 \\ y'=2*( \sqrt{x} + \dfrac{1}{ \sqrt{x} } )*( \dfrac{1}{2 \sqrt{x} } - \dfrac{3}{2x \sqrt{x} } )$

If x=2  then
$y'=2*( \sqrt{2} + \dfrac{1}{ \sqrt{2} } )*( \dfrac{1}{2 \sqrt{2} } - \dfrac{3}{2*2* \sqrt{2} } )\\ =2* \dfrac{2+ \sqrt{2} }{ \sqrt{2} } * \dfrac{1}{4*\sqrt{2} } *(-1)\\ =- \dfrac{2+ \sqrt{2} }{4}$