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Ksenya-84 [330]
1 year ago
9

Kinematics of particles problems and solutions pdf

SAT
1 answer:
iragen [17]1 year ago
6 0

The acceleration of the pendulum mass D is; r"_d =  [x''(t) + lθ'' cos θ - lθ'² sin θ]i - l[θ'' sin θ - θ'² cos θ]j

<h3>What is Kinematics of particles?</h3>

Kinematics is the study of the geometry of motion of particles, rigid bodies, etc., disregarding the forces associated with these motions. However, Kinematics of a particle is the motion of a point in space.

From the sample problem, we can solve it using the (x, y, z) coordinate system to get;

r_c = x(t) i

r_d = [x(t) + l sin θ]i + l cos θ j

Finding the first derivative of r_d gives velocity as;

r'_d =  [x'(t) + lθ' cos θ]i - lθ' sin θ j

Taking the second derivative of r_d gives the acceleration as;

r"_d =  [x''(t) + lθ'' cos θ - lθ'² sin θ]i - l[θ'' sin θ - θ'² cos θ]j

A sample problem of kinematics of particles is;

A block C slides along the horizontal rod, while a pendulum attached to the block can swing in the vertical plane. Find the acceleration of

the pendulum mass D.

Read more about Kinematics of Particles at; brainly.com/question/26269548

#SPJ1

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Identify the reference angle es001-1. Jpg for each given angle, es001-2. Jpg. Es001-3. Jpg degrees. Es002-1. Jpg degrees. Es003-
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The reference angle is the smallest angle between the terminal side and the x-axis.

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Hence, the reference angle of 300 degrees is 60 degrees

(2)\ \theta = 225^o

225 degrees is in the 3rd quadrant.

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\alpha = 225 - 180

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Hence, the reference angle of 225 degrees is 45 degrees

(3)\ \theta = 480^o

480 degrees is in the 2nd quadrant (i.e. 480 - 360 = 120)

So, the reference angle is

\alpha = 180 - \theta

\alpha = 180 - 120

\alpha = 60^o

Hence, the reference angle of 480 degrees is 60 degrees

(2)\ \theta = -210^o

-210 degrees is in the 2nd quadrant (i.e. 360 - 210 = 150)

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Answer: C.) The actions of consumers in response to changes in price.

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I hope this helped !

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