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mezya [45]
2 years ago
8

Sketch a graph of the following rational function: h(x)= x²-1/ x³-2x²-x+2​

Mathematics
1 answer:
Naddika [18.5K]2 years ago
4 0

Note that

\frac{x^2-1}{x^3 - 2x^2 -x+2}=\frac{x^2 -1}{x^2 (x-2)-(x-2)}=\frac{x^2 -1}{(x^2 -1)(x-2)}

So, for all x \neq \pm 1, f(x)=\frac{1}{x-2}.

So, the graph looks like something like as following in the image.

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5 0
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3 years ago
Write a quadratic relation in the form y = ax2 + bx + c with roots 4 and - 3 and
pochemuha

Answer:

y =  2*x^2 - 2*x - 24

Step-by-step explanation:

If we have a quadratic function with roots a and b, we can write the equation for that function as:

y = f(x) = A*(x - a)*(x - b)

Where A is the leading coefficient.

In this case, we know that the roots are: 4 and -3

Then the function will be something like:

f(x) = A*(x - 4)*(x - (-3) )

f(x) = A*(x - 4)*(x + 3)

Now we need to determine the value of A.

We also know that the graph of the function passes through the point (3, -12)

This means that:

f(3) = -12

Then:

-12 = A*(3 - 4)*(3 + 3)

-12 = A*(-1)*(6)

-12 = A*(-6)

-12/-6 = A

2 = A

Then the equation is:

y = f(x) = 2*(x - 4)*(x + 3)

Now we need to write this in standard form, so we just need to expand the equation:

y = f(x) = 2*(x^2 + x*3 - x*4 - 4*3)

y = f(x) = 2*(x^2 - x - 12)

y = f(x) = 2*x^2 - 2*x - 24

Then the relation is:

y =  2*x^2 - 2*x - 24

4 0
3 years ago
What is the equation of the line passing through points (1,1) and (3,-5)
seraphim [82]

Answer:

m=-3

Step-by-step explanation:

5 0
3 years ago
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