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1 year ago

PLEASE HELP ME SOLVE THE QUESTION BELOW

Mathematics

1 answer:

Troyanec [42]1 year ago

5 0

For Ann and Tom to have $20,000 at the end of 10 years, they must deposit a sum of $6,131.14.

<h3>What is the principal?</h3>

To calculate the sum of money they must deposit, use the compound interest formula.

From the compound interest formula;

P = A / ( 1 + r/n )^(nt)

Given that;

Final amount A = 20,000
Interest rate r = 12% = 12/100 = 0.12
Compound n = quarterly = 4
Time t = 10 years
Principal P = ?

P = A / ( 1 + r/n )^(nt)

P = 20,000 / ( 1 + 0.12/4 )^(4×10)

P = 20,000 / ( 1.03)^40

P = 20,000 / 3.26203779

P = $6,131.14

Therefore, for Ann and Tom to have $20,000 at the end of 10 years, they must deposit a sum of $6,131.14.

Learn more about compound interest here: brainly.com/question/27128740

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3 years ago

Find the perimeter of the window to the nearest hundredth.<br><br> also how do you do it?

k0ka [10]

<em>I am assuming the picture is of a stained glass window in the shape of a semicircle</em>.

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$\frac{1}{2}$ π × 3 + 3.

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6 0

3 years ago

PLEASE I NEED HELP ASAP

zysi [14]

Answer:

option C is the correct ans..

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A function f from A to B is a relation from A to B which assosciates each element of A to a unique element of B..

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3 years ago

you measure the period of a mass oscillating on a vertical spring ten times as follows: period (s): 1.06, 1.31, 1.28, 0.99, 1.48

lidiya [134]

The mean and (sample) standard deviation σ = 0.2098.

<h3>What exactly would the standard deviation indicate?</h3>

The term "standard deviation" (or "") refers to the degree of dispersion of the data from the mean. Data are grouped around the mean when the standard deviation is low, and are more dispersed when the standard deviation is high.

<h3>According to given information:</h3>

The mean is the product of the dataset's total and the sample size. Mathematically.

$\bar{x}=\frac{\sum X_i}{N}$

The individual periods are Xi.

The sample size is N.

$\sum X i$ = 1.06 + 1.31 + 1.28 + 0.99,+ 1.48 + 1.37+ 0.98 + 1.31 + 1.59 + 1.55

$\sum X i$ = 12.92

N = 10

While substituting the value we get:

x = 12.96/10

x = 1.292

The samples' average is 1.292.

The standard deviation:

$\sigma=\sqrt{\frac{\sum(x-\bar{x})^2}{N}}$

$\sum(x-\bar{x})^2$ = (1.48-1.292)^2+(1.37-1.292)^2+(0.98-1.292)^2+(1.31-1.292)^2+(1.59-1.292)^2+(1.55-1.292)^2.

$\sum(x-\bar{x})^2$ = 0.43996

Putting into the formula we get:

$\sigma=\sqrt{\frac{0.43996}{10}}$

σ = √(0.043996)

σ = 0.2098

The mean and (sample) standard deviation σ = 0.2098.

To know more about standard deviation visit:

brainly.com/question/18521100

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I understand that the question you are looking for is:

You measure the period of a mass oscillating on a vertical spring ten times as follows:

Period (s): 1.06, 1.31, 1.28, 0.99, 1.48, 1.37, 0.98, 1.31, 1.59, 1.55

Required:

What are the mean and (sample) standard deviation?

a. Mean: 1.228, Standard Deviation: 0.2135

b. Mean: 1.325, Standard Deviation: 0.1674

c. Mean: 1.292. Standard Deviation: 0.2211

d. Mean: 1.228, Standard Deviation: 0.2098

e. Mean: 1.292, Standard Deviation: 0.2135

7 0

1 year ago