A signalized intersection has a cycle length of 70 seconds. For one traffic movement, the displayed all-red time is set to 2 sec
1 answer:
Answer:
the displayed green time for the traffic movement is 30 seconds
Step-by-step explanation:
Given the data in the question;
Cycle length; C = 70 seconds
Displayed all-red time; AR = 2 seconds
Displayed yellow time; Y = 5 seconds
Effective red time; r = 37 seconds
total lost time per cycle; = 4 seconds
the displayed green time for the traffic movement; G = ?
First we determine the Effective green time ( g );
Effective red time; r = Cycle length; C - Effective green time ( g )
so,
Effective green time ( g ) = C - r
we substitute
Effective green time ( g ) = 70 seconds - 37 seconds
Effective green time ( g ) = 33 seconds
Now,
Effective green time ( g ) = displayed green time; G + Displayed yellow time; Y + Displayed all-red time; AR - total lost time per cycle;
i.e
g = G + Y + AR -
we substitute
33 = G + 5 + 2 - 4
33 = G + 3
G = 33 - 3
G = 30 seconds
Therefore, the displayed green time for the traffic movement is 30 seconds
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So let's plug it all in from above:
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To total amount is 78
Jake caught 22 so
78 - 22 = 56
So Andy and Damon caught 56 between the two of them
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56 - 30 = 26
Damon caught at most 26
And caught at most 36
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Damon caught at least 20
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Jake caught 22 so
78 - 22 = 56
So Andy and Damon caught 56 between the two of them
Andy caught at least 30
56 - 30 = 26
Damon caught at most 26
And caught at most 36
56 - 36 = 20
Damon caught at least 20
The answer is
The answer is A
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ANSWER
D. (-2,5)
EXPLANATION
The given equations are
and
We substitute equation (2) into equation (1) to get,
We expand the bracket to get,
Grouping similar terms, we obtain,
Simplify to get,
Divide both sides by 13 to obtain,
This implies that,
The solution is (-2,5)
D. (-2,5)
EXPLANATION
The given equations are
and
We substitute equation (2) into equation (1) to get,
We expand the bracket to get,
Grouping similar terms, we obtain,
Simplify to get,
Divide both sides by 13 to obtain,
This implies that,
The solution is (-2,5)