A signalized intersection has a cycle length of 70 seconds. For one traffic movement, the displayed all-red time is set to 2 sec
1 answer:
Answer:
the displayed green time for the traffic movement is 30 seconds
Step-by-step explanation:
Given the data in the question;
Cycle length; C = 70 seconds
Displayed all-red time; AR = 2 seconds
Displayed yellow time; Y = 5 seconds
Effective red time; r = 37 seconds
total lost time per cycle; = 4 seconds
the displayed green time for the traffic movement; G = ?
First we determine the Effective green time ( g );
Effective red time; r = Cycle length; C - Effective green time ( g )
so,
Effective green time ( g ) = C - r
we substitute
Effective green time ( g ) = 70 seconds - 37 seconds
Effective green time ( g ) = 33 seconds
Now,
Effective green time ( g ) = displayed green time; G + Displayed yellow time; Y + Displayed all-red time; AR - total lost time per cycle;
i.e
g = G + Y + AR -
we substitute
33 = G + 5 + 2 - 4
33 = G + 3
G = 33 - 3
G = 30 seconds
Therefore, the displayed green time for the traffic movement is 30 seconds
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Answer:
Step-by-step explanation:
To sketch a quadratic function we need two things:
1) Nature of the curve
2) Vertex
3) y-intercept
The completing square form of the quadratic equation is:
where,
a represents the nature of the graph it can be maximum or minimum , meaning, if a > 0 then minimum(u shaped curve/happy face) and if a < 0 then maximum(n shaped curve/sad face).
h represents the x-coordinate of the vertex.
k represents the y-coordinate of the vertex.
Now if we compare g(x) with our completing square form we get the following:
When we simply compare the following we get ,
a = 1 , which means a > 0 since 1 is greater than 0 the nature of the curve will be minimum(happy face/u shaped)
h = 4, which means the x-coordinate of the vertex is 4
k = 12, which means the y-coordinate of the vertex is 12
Now we have the nature of the curve, we have the vertex now all we need is the y-intercept.
For y-intercept:
For y-intercept meaning at which point will the graph cross the y-axis(0 , y)
For that we expand the formula and turn it into the standard quadratic equation form by using the formula (a - b)^2
now we compare with the standard quadratic form:
here c is the y-intercept and while comparing we can see that c = 28 ,
so the curve cuts the y-axis at (0 , 28)
So we have all the three things that we need to graph our function.
So we just plot the y-intercept , the vertex , and join the dots. Just a tip draw a dotted line on the x-coordinate of the vertex because the vertex point is also called as a turning point where the graph goes in the opposite direction just like a mirror reflection. I attached 2 images you can check them out. One is handmade(i know i suck at drawing but still xD) , one is sketched by online graphing calculator.
