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nata0808 [166]
2 years ago
9

an automated tool known as log can consolidate system logs, perform comparative analysis and detect common occurrences or behavi

or of interest
SAT
1 answer:
dalvyx [7]2 years ago
4 0

Log analysis tools  is an automated tool known as log can consolidate system logs, perform comparative analysis and detect common occurrences or behavior of interest

<h3>What is a log analysis tool?</h3>

Log analysis tools are known to be tools that aids in the generating of web, streaming and other kinds of mail server statistics graphically.

Hence, Log analysis tools  is an automated tool known as log can consolidate system logs, perform comparative analysis and detect common occurrences or behavior of interest

Learn more about automated tool from

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people don't judge for let other people get bullied not nice and that means your not letting god in but the devil in
S_A_V [24]

Answer:

of course

Explanation:

6 0
3 years ago
Determine the empirical formula of a compound containing 47. 37 grams of carbon, 10. 59 grams of hydrogen, and 42. 04 grams of o
Effectus [21]

Considering the definition of empirical formula, the empirical formula is C₃H₈O₂ and the molecular formula is C₉H₂₄O₆.

<h3>Definition of empirical formula</h3>

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

<h3>Empirical formula in this case</h3>

In this case, you have:

  • Carbon (C): 47.37 grams
  • Hydrogen (H): 10.59 grams
  • Oxygen (O):  42.04 grams

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

  • Carbon (C): \frac{47.37 grams}{12 \frac{g}{mole} }= 3.95 moles
  • Hydrogen (H): \frac{10.59 grams}{1 \frac{g}{mole} }= 10.59 moles
  • Oxygen (O):  \frac{42.04 grams}{16 \frac{g}{mole} }= 2.63 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

  • Carbon (C): \frac{3.95 moles}{2.63 moles }= 1.5
  • Hydrogen (H): \frac{10.59 moles}{2.63 moles }= 4
  • Oxygen (O):  \frac{2.63 moles}{2.63 moles }= 1

Finally, since in the empirical formula the numbers of moles must be expressed in whole numbers, the ratio of atoms is multiplied by some number with which everything is obtained in simple whole numbers (in this case by 2):

  • Carbon (C): 1.5× 2= 3
  • Hydrogen (H): 4× 2= 8
  • Oxygen (O):  1× 2= 2

Therefore the C: H: O mole ratio is 3: 8: 2

Finally, the empirical formula is C₃H₈O₂.

<h3>Molecular formula</h3>

To obtain the molecular formula you must relate its molecular weight (PMc) with the molecular weight of the empirical formula (PMfe).

PMfe= PM (C₃H₈O₂)= 76 g/mole

The molar mass of the compound (PMc) was determined to be 228.276 g/mol. Dividing this mass PMc by the molar mass of the empirical formula PMfe gives:

228.276 g/mol ÷ 76 g/mole= 3

This means that in the molecular formula there are 3 unit formulas (empirical formulas), so it is necessary to multiply the number of all atoms by 3.

Then, the molecular formula is C₉H₂₄O₆.

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3 0
2 years ago
You have been called to testify as an expert witness in a trial.
aivan3 [116]

Answer: In court a witness is a person who saw it all happen and if your a witness the court would want you to explain what you saw or what happened.

Explanation:

5 0
2 years ago
Pensamiento filosofico<br>ayudemen por fis​
dem82 [27]

Answer:

philosophical thought help them by fis???

Explanation:

7 0
3 years ago
Tyler answered 26 of 40 test questions correctly. What percent did he answer correctly?.
wariber [46]

Answer:

26 of 40 so you need to multiply 40X65% = 26 so 65% is the answer

4 0
2 years ago
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