Question

You throw a ball at a height of 6 feet above the

Answer 1

Answer:

0.375 second and 3.5 second

Step-by-step explanation:

The position can be modeled by a quadratic function $\displaystyle{h=-16t^2+62t+6}$. We are tasked to find the time when a ball reaches a height of 27 feet. Therefore, let h = 27:

$\displaystyle{27=-16t^2+62t+6}$

Solve for t:

$\displaystyle{27-6=-16t^2+62t}\\\\\displaystyle{21=-16t^2+62t}\\\\\displaystyle{16t^2-62t+21=0}$

Since the equation is quite complicated and more time-consuming to solve, i'll skip the factoring or quadratic part:

$\displaystyle{t=0.375, 3.5}$

After done solving the equation, you'll get t = 0.375 and 3.5 seconds. These solutions are valid since both are positive values and time can only be positive.

Hence, it'll take 0.375 and 3.5 seconds for a ball to reach 27 feet.