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Vinil7 [7]
2 years ago
6

Help i made it worth a lot of points

Mathematics
2 answers:
raketka [301]2 years ago
4 0

Answer:

36x^6/y^10

Step-by-step explanation:

First evaluate the parentheses, 6x^3 x 6x^3 = 36x^6

y^5 x y^5 = y^10 ; remember m^k x m^r = m^k+r

final answer should be 36x^6/y^10

hope this helps :')

Mandarinka [93]2 years ago
4 0

Answer:

\dfrac{36x^6}{y^{10}}

Step-by-step explanation:

First, deal with the exponent 2 outside the parentheses.

Raise each factor to the second power.

(\dfrac{6x^3}{y^5})^2 =

= \dfrac{6^2(x^3)^2}{(y^5)^2}

To raise a power to a power, multiply the powers.

= \dfrac{36x^6}{y^{10}}

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Help me please translations hw
RUDIKE [14]

The locations of the vertices are shown below:

  1. (- 5, 4), (- 4, 4), (- 5, 2)
  2. (- 4, 1), (- 1, 2), (0, - 1), (- 2, - 5)
  3. (2, 5), (3, 4), (1, 2)
  4. (3, - 5), (- 2, - 3), (0, - 1)
<h3>What are the coordinates of the images resulting from a translation?</h3>

Herein we find four representations of polygons on Cartesian plane and we must determine the coordinates of the images generated by translation, a kind of rigid transformations. Translation is described by the following operation:

P'(x, y) = P(x, y) + T(x, y)

Where:

  • P(x, y) - Original point
  • P'(x, y) - Resulting point
  • T(x, y) - Translation vector

Case 1 (K(x, y) = (3, - 3), X(x, y) = (4, - 3), R(x, y) = (3, - 5), T(x, y) = (- 8, 7))

K'(x, y) = (3, - 3) + (- 8, 7) = (- 5, 4)

X'(x, y) = (4, - 3) + (- 8, 7) = (- 4, 4)

R'(x, y) = (3, - 5) + (- 8, 7) = (- 5, 2)

Case 2 (E(x, y) = (0, 2), X(x, y) = (3, 3), V(x, y) = (4, 0), Z(x, y) = (2, - 4), T(x, y) = (- 4, - 1))

E'(x, y) = (0, 2) + (- 4, - 1) = (- 4, 1)

X'(x, y) = (3, 3) + (- 4, - 1) = (- 1, 2)

V'(x, y) = (4, 0) + (- 4, - 1) = (0, - 1)

Z'(x, y) = (2, - 4) + (- 4, - 1) = (- 2, - 5)

Case 3 (G(x, y) = (- 4, 5), J(x, y) = (- 3, 4), U(x, y) = (- 5, 2), T(x, y) = (6, 0))

G'(x, y) = (- 4, 5) + (6, 0) = (2, 5)

J'(x, y) = (- 3, 4) + (6, 0) = (3, 4)

U'(x, y) = (- 5, 2) + (6, 0) = (1, 2)

Case 4 (V(x, y) = (0, 0), Y(x, y) = (- 5, 2), F(x, y) = (- 3, 4), T(x, y) = (3, - 5))

V'(x, y) = (0, 0) + (3, - 5) = (3, - 5)

Y'(x, y) = (- 5, 2) + (3, - 5) = (- 2, - 3)

F'(x, y) = (- 3, 4) + (3, - 5) = (0, - 1)

To learn more on rigid transformations: brainly.com/question/28004150

#SPJ1

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