Question

There are 3 possible genotypes: NN, MN, or MM. In a group of 500 people, the frequency of genotype NN is 40%. How many individuals would you expect to have the MN genotype

Answer 1

235 are the Individual numbers that would expect to have the MN type of genotype.

There are two equations necessary according to Hardy-Weinberg Equilibrium:-

p + q = 1

p² + 2pq + q² = 1

Let,

NN= p

NM=2pq

MM=q

So, according to the question, the frequency of genotype NN is 40%

40% of 500 = $\frac{500*40}{100} = 200$ Numbers of individuals

Frequency of individuals p = $\frac{Numbers of individuals}{Total populations}$ = $\frac{200}{400} = 0.4$

Find p² by taking the square root of p.

√(p) = √(0.4)

= 0.632

So, pp + qq = 1  

qq = 1 - pp =  1 - 0.63

q = 0.37

The allele frequencies in the population are known, now finding the frequency of heterozygous genotype.

By Multiplying 2 × p ×q  to get heterozygous genotype

2pq =  2 × 0.63 × 0.37` = 0.47

2pq = 0.47

So, 2pq × total population = 0.47 × 500 = 235, NM genotype.

Learn more about Hardy-Weinberg Equilibrium here,

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