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Semmy [17]
1 year ago
11

Can someone please help mee

Mathematics
1 answer:
cricket20 [7]1 year ago
5 0

Answer:

5/13

Step-by-step explanation:

sine=opposite/hypotenuse

cosine=adjacent/hypotenuse

opposite=-12 (I know that this is not possible)

hypotenuse=13

These are ratios, not real lengths

using the Pythagorean theorem, the other leg is 5

cos (theta)=5/13

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Suppose S and T are mutually exclusive events. Find P(S or T)? sp(S) = 6/11 and p(t)= 1/10
Sholpan [36]
Using P(A∪B) = P(A) + P (B) - P(A∩B) 
If we apply this in the question 
Then P(S∪T) = P(S) + P(T) - P (S∩T)
                      = 6/11 + 1/10 - P (S∩T)
                      = 71/110 - P (S∩T)
But events S and T are mutually exclusive events therefore, 
P(S∩T) = 0,
Hence P(S∪T) = 71/110
3 0
2 years ago
E= (6,2)(7,3)(6,-1)(5,4)
Bezzdna [24]

I think it's the last point. (5,4)

3 0
3 years ago
Solve by substitution
Hunter-Best [27]

Answer:

A

Step-by-step explanation:

y = -9 ------(1)

9x -4y = -9 -------(2)

substitute (1) into (2)

9x - 4 (-9) = -9

9x = - 45

x = -5

there you go, x = -5 and y = -9

so. (-5 , -9 )

hope this helps

please mark it brainliest

7 0
2 years ago
How to solve this problem step by step. Make brainliest answer if its done. Please
sladkih [1.3K]

D is halfway between A and B

so the coordinates of D are (2,2)

E is halfway between A and C so the coordinates of E are (-1,1)

now you need to find the gradient/slope of DE and BC using the formula:

\frac{y2 - y1}{x2 - x1}

<h3><u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>

SUB IN COORDINATES OF D AND E

\frac{1 - 2}{ - 1 - 2}

therefore the gradient of DE is 1/3.

<h3><u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>

<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>

<em>\frac{ - 2 - 0}{ - 3 - 3}</em>

therefore the gradient of BC is -2/-6 which simplifies to 1/3.

<h3>therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>

6 0
3 years ago
What is the answer to this problem? <br><br> 2 1/3 + 3 1/3 =?
Naily [24]

Answer:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

Exact Form:

173

Decimal Form:

5.¯6

Mixed Number Form:

523

Step-by-step explanation:

3 0
3 years ago
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