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2 years ago

15

Your watch currently reads “8:00.” What time did it read 24 hours earlier? Ten hours earlier? Twenty-five hours earlier? What ti

me did it read 2400 hours earlier?

1 answer:

antoniya [11.8K]2 years ago

7 0

Answer:

..l

Step-by-step explanation:

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Question is in the picture please help.

Mademuasel [1]

Answer: a

Step-by-step explanation: its getting rid of water and the original is 40

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2 years ago

Archaeologists can determine the diets of ancient civilizations by measuring the ratio of carbon-13 to carbon-12 in bones found

harkovskaia [24]

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yessirrr

Step-by-step explanation:

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2 years ago

Suppose there is a bag containing 5 red marbles (Upper R), 5 pink marbles (Upper P), 5 green marbles (Upper G), and 5 blac

Radda [10]

Answer:

In the Explanation

Step-by-step explanation:

(a)From the attached probability tree, the possible outcomes are:

RR,RP,RG,RB,PR,PP,PG,PB,GR,GP,GB,GG,BR,BP,BG,BB

(b)Probability Distribution of Drawing Pink Marbles

$\left|\begin{array}{c|c}Result&Probability\\----&----\\0&\frac{9}{16}\\----&---\\1& \frac{3}{8}\\----&---\\2&\frac{1}{16}\end{array}\right|$

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3 years ago

(cotx+cscx)/(sinx+tanx)

Butoxors [25]

Answer: $\bold{\dfrac{cot(x)}{sin(x)}}$

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

$\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)$

$\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)$

$\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}$

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3 years ago

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creativ13 [48]

There is nothing there to work with

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2 years ago