Answer:
(B) 1
Step-by-step explanation:
g(x) = ∫₂ˣ f(t) dt
Use second fundamental theorem of calculus to find g'(x).
g'(x) = f(x) d(x)/dx − f(2) d(2)/dx
g'(x) = f(x)
g(x) is a maximum when g'(x) = 0.
0 = f(x)
x = 3
So the maximum value of g(x) is:
g(3) = ∫₂³ f(t) dt
g(3) = ½ (2) (1)
g(3) = 1
Answer:
(4,5)
Step-by-step explanation:
The "feasible region" has vertices (0,0), (7,0), (5,4), and (4,5)
P = 5x + 6y
Plug in each vertices in P and find out which give maximum value
(0,0) => P= 5(0) + 6(0) = 0
(7,0) => P= 5(7) + 6(0) = 35
(5,4) => P= 5(5) + 6(4) = 49
(4,5) => P= 5(4) + 6(5) = 50
We got maximum P=50 for vertex (4,5)
So the coordinates of the point that has the maximum value is (4,5)
Answer:
152 ft³
Step-by-step explanation:
3 * 6 * 4 = 72
4 * 4 * 5 = 80
72 + 80 = 152
Answer:
p ^ q
Step-by-step explanation:
its stating that 9 it an equality with 3.
