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sineoko [7]
2 years ago
9

Show work. This is a BC calculus problem.

Mathematics
1 answer:
stepan [7]2 years ago
5 0

Answer:

D.

Step-by-step explanation:

Remember that the limit definition of a derivative at a point is:

\displaystyle{\frac{d}{dx}[f(a)]= \lim_{x \to a}\frac{f(x)-f(a)}{x-a}}

Hence, if we let f(x) be ln(x+1) and a be 1, this will yield:

\displaystyle{\frac{d}{dx}[f(1)]= \lim_{x \to 1}\frac{\ln(x+1)-\ln(2)}{x-1}}

Hence, the limit is equivalent to the derivative of f(x) at x=1, or f’(1).

The answer will thus be D.

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Answer:

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Step-by-step explanation:

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Prove : (sec θ - tan θ )^2 = 1 - sin θ /1+sin θ
labwork [276]
(sec x - tan x)^2 \\  \\ = sec^2x - 2 sec x tan x + tan^2 x \\  \\ =(1+tan^2 x) - 2 sec x tan x +tan^2 x \\  \\ =1 - 2 sec x tan x + 2 tan^2 x \\  \\ = 1 - 2tan x(sec x - tan x) \\  \\ =1 - \frac{2 sin x}{cos x} (\frac{1-sin x}{cos x}) \\  \\ = 1 - \frac{2 sin x (1-sin x)}{cos^2 x} \\  \\ =1 - \frac{2 sin x (1-sin x)}{1-sin^2 x} \\  \\ =1 - \frac{2 sin x (1-sin x)}{(1-sin x)(1+sin x)} \\  \\ =1-\frac{2 sin x}{1+sin x}
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3 years ago
1.The base length of a rectangle is multiplied by 8. How does this affect the area?
earnstyle [38]

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Step-by-step explanation:

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3 0
3 years ago
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The annual rainfall (in inches) in a certain region is normally distributed with = 40 and = 4. What is the probability that star
sdas [7]

Answer:

0.93970

Step-by-step explanation:

Solution:-

- Denote a random variable "X" The annual rainfall (in inches) in a certain region . The random variable follows a normal distribution with parameters mean ( μ ) and standard deviation ( σ ) as follows:

                          X ~ Norm ( μ , σ^2 )

                          X ~ Norm ( 40 , 4^2 ).

- The probability that it rains more than 50 inches in that certain region is defined by:

                          P ( X > 50 )

- We will standardize our test value and compute the Z-score:

                          P ( Z > ( x - μ )  / σ )

Where, x : The test value

                          P (  Z > ( 50 - 40 )  / 4 )

                          P (  Z > 2.5 )

- Then use the Z-standardize tables for the following probability:

                          P ( Z < 2.5 ) = 0.0062

Therefore,          P ( X > 50 ) = 0.0062

- The probability that it rains in a certain region above 50 inches annually. is defined by:

                           q = 0.0062 ,

- The probability that it rains in a certain region rains below 50 inches annually. is defined by:

                           1 - q = 0.9938

                           n = 10 years   ..... Sample of n years taken

- The random variable "Y" follows binomial distribution for the number of years t it takes to rain over 50 inches.

                          Y ~ Bin ( 0.9938 , 0.0062 )

- The probability that it takes t = 10 years for it to rain:

                         =  10C10* ( 0.9938 )^10 * ( 0.0062 )^0

                         = ( 0.9938 )^10

                         = 0.93970

3 0
3 years ago
Please help ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.
sweet [91]

Answer:

  D.  Minimum at (3, 7)

Step-by-step explanation:

We can add and subtract the square of half the x-coefficient:

  y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2

  y = (x -3)^2 +7 . . . . . simplify to vertex form

Comparing this to the vertex for for vertex (h, k) ...

  y = (x -h)^2 +k

We find the vertex to be ...

  (3, 7) . . . . vertex

The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.

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