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Fynjy0 [20]
3 years ago
12

steven has a rectangular rug with a perimeter of 16 feet the width of the rug is 5 feet what is the length of the rug

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
8 0
To find perimeter you must do 2l+2w so to find the length you have to plug in 5 2(5)+2l 10+2l =16 -10. -10 2l=6 /2. /2 L=3
Travka [436]3 years ago
4 0

-- "Perimeter" means all the way around, all four sides.

-- That's two lengths and two widths.

-- So one length and one width is half of the perimeter.

-- If the perimeter is 16-ft, then one length + one width is 8-ft.

-- If the width is 5-ft, then the length is (8 - 5) = 3-ft.
 
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Simplify. 6m+7n+5m−3nhow to earn points
lorasvet [3.4K]

Answer:

11m + 4n ...............

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I need help pleases I wil give brainyless
erica [24]

Answer: Let's start by writing down coordinates of all points:

A(0,0,0)

B(0,5,0)

C(3,5,0)

D(3,0,0)

E(3,0,4)

F(0,0,4)

G(0,5,4)

H(3,5,4)

a.) When we reflect over xz plane x and z coordinates stay same, y coordinate  changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.

A(0,0,0)

Reflecting

A(0,0,0)

B(0,5,0)

Reflecting

B(0,-5,0)

C(3,5,0)

Reflecting

C(3,-5,0)

D(3,0,0)

Reflecting

D(3,0,0)

b.)

A(0,0,0)

Moving

A(-2,-3,1)

B(0,-5,0)

Moving

B(-2,-8,1)

C(3,-5,0)

Moving

C(1,-8,1)

D(3,0,0)

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D(1,-3,1)

Hope this helps plz mark brainliest

Step-by-step explanation:

3 0
2 years ago
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Let f(x) = log(x). Find values of a such that f(kaa) = kf(a).
meriva

Answer:

a = k^{\frac{1}{k-2}}

Step-by-step explanation:

Given:

f(x) = log(x)

and,

f(kaa) = kf(a)

now applying the given function, we get

⇒ log(kaa) = k × log(a)

or

⇒ log(ka²) = k × log(a)

Now, we know the property of the log function that

log(AB) = log(A) + log(B)

and,

log(Aᵇ) = b × log(A)

Thus,

⇒ log(k) + log(a²) = k × log(a)         (using log(AB) = log(A) + log(B) )

or

⇒ log(k) + 2log(a) = k × log(a)            (using log(Aᵇ) = b × log(A) )

or

⇒ k × log(a) - 2log(a) = log(k)

or

⇒ log(a) × (k - 2) = log(k)

or

⇒ log(a) = (k - 2)⁻¹ × log(k)

or

⇒ log(a) = \log(k^{\frac{1}{k-2}})          (using log(Aᵇ) = b × log(A) )

taking anti-log both sides

⇒ a = k^{\frac{1}{k-2}}

3 0
3 years ago
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