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2 years ago

Can someone help me with the first question please

Mathematics

1 answer:

snow_lady [41]2 years ago

3 0

Answer:

Step-by-step explanation:

The median of a triangle is the line through a vertex and the midpoint of the opposite side. The median of ΔXYZ from vertex Y will be the line through point Y and the midpoint of XZ.

<h3>Midpoint</h3>

The midpoint of XZ is the average of the coordinates of X and Z.

M = (X +Z)/2

M = ((1, -2) +(8, -7))/2 = (9, -9)/2 = (4.5, -4.5)

<h3>Line through two points</h3>

The slope of the median can be found using the slope formula:

m = (y2 -y1)/(x2 -x1)

The slope of line YM is ...

m = (-4.5 -4)/(4.5 -7) = -8.5/-2.5 = 17/5

The point-slope form of the equation of a line is ...

y -k = m(x -h) . . . . . . line with slope m through point (h, k)

The line with slope 17/5 through point Y(7, 4) is ...

y -4 = 17/5(x -7)

Subtracting the right side, and multiplying by 5 gives ...

5(y -4) -17(x -7) = 0

5y -17x +99 = 0 . . . . equation of the median through Y

You might be interested in

the equation of a circle in general form is x squared + y squared + 20x + 12 y + 15 equals 0what is the equation of the circle i

Marrrta [24]

Answer: $(x+10)^2+(y+6)^2=121$

Step-by-step explanation:

The equation of a circle in the general form is:

$ax^{2}+by^2+cx+dy+e=0$

The equaton of a circle in standard form is:

$(x-h)^2+(y-k)^2=r^2$

Where the center is at <em>(h, k)</em> and <em>r</em> is the radius

To write the equation of a circle from general form to standard form, you must complete the squaare, as you can see below:

1- Given the equation in general form:

$x^{2}+y^2+20x+12y+15=0$

2- Complete the square:

-Group the like terms and move the constant to the other side.

- Complete the square on the left side of the equation.

- Add the same value to the other side.

Then you obtain:

$(x^{2}+20x)+(y^2+12y)=-15\\(x^2+20x+(\frac{20}{2})^2)+(y^2+12y+(\frac{12}{2})^2)=-15+(\frac{20}{2})^2+(\frac{12}{2})^2\\\\(x+10)^2+(y+6)^2=-15+100+36\\(x+10)^2+(y+6)^2=121$

4 0

3 years ago

I did something wrong could you help?

posledela

Answer:

Slope = 1/2

y-intercept = 30

Equation : y = 1/2x + 30

D. 150 miles

Step-by-step explanation:

We can use the two visible points you marked on the graph.

They are (0,30) which is also the y-intercept and (20,40).

Calculate change of y over change of x.

10/20 or 1/2

So the slope is 1/2 and the y-intercept is 30.

Therefore, using y = mx + b form, the equation is y = 1/2x + 30

Then, to find how many miles you drove if the cost was $105, we can plug in 105 for y in the equation.

105 = 1/2x + 30

75 = 1/2x

x = 150

8 0

4 years ago

Part 1: Identify key features and graph a parabola from standard form.

astraxan [27]

Wait i will tell you soon dont worry, im out now sorryy ^.^

4 0

3 years ago

What two whole numbers is 29−−√ between?: 3 and 4 4 and 5 5 and 6 6 and 7

jolli1 [7]

The two whole numbers are 5 and 6 ⇒ 3rd answer

Step-by-step explanation:

To prove that a square root number lies between which two consecutive integers do that

Find a square number less than the number under the root
Find a square number greater than the number under the root
Find the square root of the square numbers, they will be the two integers that the root lies between them

∵ The number is $\sqrt{29}$

- Find a square number less than 29

∵ 25 is a square number

∵ 25 is less than 29

- Find a square number greater than 29

∵ 36 is a square number

∵ 36 is greater than 29

∴ 25 < 29 < 36

- Take √ for each number

∴ $\sqrt{25}$ < $\sqrt{29}$ < $\sqrt{36}$

∵ $\sqrt{25}$ = 5

∵ $\sqrt{36}$ = 6

∴ 5 < $\sqrt{29}$ < 6

The two whole numbers are 5 and 6

Learn more:

You can learn more about the numbers in brainly.com/question/9621364

#LearnwithBrainly

8 0

3 years ago

You are testing the claim that the mean GPA of night students is different from the mea GPA of day students. You sample 20 night

svetlana [45]

Answer:

As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.

Step-by-step explanation:

Here n= 20

Sample mean GPA = x`= 2.84

Standard mean GPA = u= 2.55

Standard deviation = s= 0.45.

Level of Significance.= ∝ = 0.01

The hypothesis are formulated as

H0: u1=u2 i.e the GPA of night students is same as the mean GPA of day students

against the claim

Ha: u1≠u2

i.e the GPA of night students is different from the mea GPA of day students

For two tailed test the critical value is z ≥ z∝/2= ± 2.58

The test statistic

Z= x`-u/s/√n

z= 2.84-2.55/0.45/√20

z= 0.1441

As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.

8 0

3 years ago