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lara [203]
3 years ago
10

∠A=24∘and ∠B=24∘ What term can be used to describe these two angles?

Mathematics
2 answers:
NeTakaya3 years ago
5 0
Your answer will be congruent
sergey [27]3 years ago
3 0
The answer is 4, or congruent
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the number m and 5/8 are additive inverses.drag and drop m to their correct positions on the number line.drag and drop the label
monitta

The additive inverse of a number is that number with its sign changed.

The additive inverse of 5/8 is -5/8, so that is the value of <em>m</em>.

The sum of a number and its additive inverse is <em>zero</em>. (This is actually the definition of <em>additive inverse</em>.)

5/8 is found at 5/8 on the number line.

m is found at -5/8 on the number line.

"sum" is found at 0 on the number line.

3 0
4 years ago
fills an aquarium to a depth of 3/4 meters in 2 2/5 minutes what is the unit rate in minutes per meter
Kisachek [45]

Answer:

 3 1/5 minutes per meter

Step-by-step explanation:

To find the rate in minutes per meter, divide the number of minutes by the number of meters:

  (2.4 min)/(0.75 m) = 3.2 min/m = 3 1/5 minutes per meter

6 0
3 years ago
The pH of a substance added to a citrate buffer, y, depending on the ratio of citric acid to sodium citrate, x, can be modeled u
Charra [1.4K]

Answer:

Yes it's A. 0.79

Step-by-step explanation:

You plug in 6.5 into the y-value since it asks to find the ratio,x, if the pHis 6.5. Then you can solve using a calculator to get 0.79432, or 0.79

5 0
3 years ago
Read 2 more answers
|x-3|&lt;2<br> |4x+1|&gt;0<br> |x-1|&lt;5<br> Ayudaaaaaaa pleaseeeee
Dafna11 [192]

Recuerda que

• |<em>x</em>| = <em>x</em> si <em>x</em> ≥ 0

• |<em>x</em>| = -<em>x</em> si <em>x</em> < 0

Necesitas considerar dos casos:

• si <em>x</em> - 3 ≥ 0,

|<em>x</em> - 3| < 1   ⇒  <em>x</em> - 3 < 1   ⇒   <em>x</em> < 4

• si <em>x</em> - 3 < 0,

|<em>x</em> - 3| < 1   ⇒   -(<em>x</em> - 3) = 3 - <em>x</em> < 1   ⇒   -<em>x</em> < -2   ⇒   <em>x</em> > 2

Entonces la solución consta de todos los números reales <em>x</em> tales que <em>x</em> > 2 y <em>x</em> < 4, o simplemente 2 < <em>x</em> < 4.

El método para resolver las otras desigualdades es el mismo.

|4<em>x</em> + 1| > 0   ⇒   4<em>x</em> + 1 > 0   o   -(4<em>x</em> + 1) > 0

…   ⇒   4<em>x</em> + 1 > 0   o   -4<em>x</em> - 1 > 0

…   ⇒   4<em>x</em> > -1   o   -4<em>x</em> > 1

…   ⇒   <em>x</em> > -1/4   o   <em>x</em> < -1/4

⇒   <em>x</em> ≠ -1/4

|<em>x</em> - 1| < 5   ⇒   <em>x</em> - 1 < 5   o   -(<em>x</em> - 1) < 5

…   ⇒   <em>x</em> - 1 < 5   o   -<em>x</em> + 1 < 5

…   ⇒   <em>x</em> < 6   o   -<em>x</em> < 4

…   ⇒   <em>x</em> < 6   o   <em>x</em> > -4

⇒   -4 < <em>x</em> < 6

7 0
3 years ago
A quadratic equation is shown below:
mylen [45]
The radicand of a quadratic is b^2-4ac.

If it is greater than zero, there are two real solutions

If it is equal to zero, there is one real solution

If it is less than zero, there are no real solutions (though there are two imaginary solutions)

In this case the discriminant is 256-2160 so it is less than zero.

Therefore there are no real solutions, though there are two imaginary solutions, specifically (16±i√-1904)/18
4 0
3 years ago
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