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nikitadnepr [17]
2 years ago
12

What is 681x239 please help

Mathematics
2 answers:
inysia [295]2 years ago
8 0

162,759 is answer

happy to help

dmitriy555 [2]2 years ago
3 0

681×239 = 162,759

..... ......

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A b c d I dont know what to choose
Aleks04 [339]

Answer:

Is this like a random question or did you forget to put something? But if it is then B ig

Step-by-step explanation:

5 0
3 years ago
Students in Mrs. Walsh's math class wanted to know the favorite snacks of students in the school. How could they generate a rand
denis23 [38]
There are several ways this can be accomplished.  Students could survey every 20 students until they've asked 100 students, or they could ask 1 or 2 people at each cafeteria table during each lunch, just for examples.
8 0
3 years ago
Which of the following expressions should be simplified using the zero power property? Select all that apply.
lys-0071 [83]

The expressions that should be simplified using the zero power property are ( r⁶ )⁰, (l⁷/l⁷), and m².m⁻². The correct options are A, C, and E.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The expressions that should be simplified using the zero power property are:-

( r⁶ )⁰     =  r⁰ = 1

(l⁷/l⁷)     =  l⁷⁻⁷ = l⁰ = 1

m².m⁻² =  m²⁻² = m⁰ = 1

Therefore, the expressions that should be simplified using the zero power property are ( r⁶ )⁰, (l⁷/l⁷), and m².m⁻². The correct options are A, C, and E.

To know more about Expression follow

brainly.com/question/723406

#SPJ1

5 0
1 year ago
Please Help!!!
stepan [7]

x + 20 = 44

x = 40 - 22

x = 18

Your answer: 18 square inches.

Hope this helps!

8 0
3 years ago
Let f(x) = -5e^(-x/3)<br><br> Find f^(6) (1)
Luba_88 [7]

Let's take the first derivative:

f'(x) = (-5e^{-x/3})' = -5 \times (e^{-x/3})' = -5e^{-x/3} \times \left(-\dfrac{1}{3}\right) = \dfrac{5}{3}e^{-x/3}.

Notice that we can write this as:

f'(x) = -\dfrac{f(x)}{3}.

By taking the derivative of both sides n times, we get:

f^{(n+1)}(x) = -\dfrac{f^{(n)}}{3}.

This means that each time you take a derivative, a factor of -\dfrac{1}{3} will appear. So we conclude that:

f^{(n)}(x) = \left(-\dfrac{1}{3}\right)^nf(x).

Taking n=6 and x=1, we get:

f^{(6)}(1) = \left(-\dfrac{1}{3}\right)^6 f(1) = \dfrac{-5e^{-1/3}}{729} = -\dfrac{5}{729}e^{-1/3}.

So we finally get:

\boxed{-\dfrac{5}{729}e^{-1/3}}.

6 0
3 years ago
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