(15–7xy^2)–(y^3–y^2x–15)

Mathematics

2 answers:

Vitek1552 [10]4 years ago

6 0

My answer is: -6xy2 - y3<span> + 30
Hope this helps bye</span>

blsea [12.9K]4 years ago

5 0

15 - 7xy^2 - (y^3 - y^2x - 15)

Distribute negative sign
15 - 7xy^2 + -1(y^3 - y2x - 15)
15 + -7xy^2 + -1y^3 + -1(-xy^2) + (-1)(-15)
15 + -7xy^2 + -y^3 + x^2 + 15

Combine like terms
15 + - 7xy^2 + -y^3 +xy^2 + 15
( -7xy^2 + xy^2) + (-y^3) + (15 + 15)
-6xy^2 + -y^3+ 30

= -6xy^2 + -y^3+ 30

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