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vlada-n [284]
2 years ago
6

Can someone help me with these problems and show work

Mathematics
1 answer:
vazorg [7]2 years ago
4 0

Answer:

Khan Academy.

Step-by-step explanation:

You can go on khan academy and search up "percentages and numbers." The videos should immediately pop up. there are also lessons if you don't want to risk getting your problem wrong. If you are still confused and do not understand please just comment and I will respond.

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A merchant sells goods which cost $240 for $299. What percentage is his profit of the cost price?​
Schach [20]

Answer:

24.58%

Step-by-step explanation:

Given that,

Initial cost = $240

Final cost = $299

We need to find the percentage in his profit of the cost price.

Profit = Final cost - Initial cost

= $299 - $240

= $59

Percentage,

\%=\dfrac{59}{240}\times100\\\\=24.58\%

So, the required percentage is equal to 24.58%.

5 0
3 years ago
If the value of y varies directly with x, which function represents the relationship between x and y when y= 16/5 and x = 20?​
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Orchards Osage palsy buds
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If each student brought in 3 valentines for each student of the (84) 5th grade students, how many valentines would they bring? I
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Answer:

They would have to buy Seven.

8 0
3 years ago
Xavier is building a triangular fence the length of the second side will be 1 foot longer than the length of the first side the
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Answer:

22

Step-by-step explanation:

3 0
3 years ago
A group of 59 randomly selected students have a mean score of 29.5 with a standard deviation of 5.2 on a placement test. What is
Otrada [13]

Answer:

29.5+/-1.11

= ( 28.39, 30.61)

Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 29.5

Standard deviation r = 5.2

Number of samples n = 59

Confidence interval = 90%

z-value (at 90% confidence) = 1.645

Substituting the values we have;

29.5+/-1.645(5.2/√59)

29.5+/-1.645(0.676982337100)

29.5+/-1.113635944529

29.5+/-1.11

= ( 28.39, 30.61)

Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)

7 0
3 years ago
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