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Mariulka [41]
3 years ago
15

find the difference between the points (-7,6) and (7,6) IM GOING CRAZY WITH THE POINT TODAY WORTH A LIFE TIME GET IT CORRECT YOU

GET BRAINLEST YES SIRR
Mathematics
1 answer:
sladkih [1.3K]3 years ago
7 0

Answer: 14

Step-by-step explanation:

For:

(X1, Y1) = (-7, 6)

(X2, Y2) = (7, 6)

Distance Equation Solution:

=(7−(−7))2+(6−6)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√

=(14)2+(0)2‾‾‾‾‾‾‾‾‾‾‾√

=196+0‾‾‾‾‾‾‾√

=1‾√96

=14

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You rent an apartment that costs
Inessa [10]

Answer:

$2,660

Step-by-step explanation:

9.5% of 1300 is 123.5

So to figure out what the rent would cost in 11 years, we just have to multiply 123.5 by 11.

123.5 × 11 = 1358.5

We can then add that number to 1300.

1358.5 + 1300 = $2658.5

Then we round.

Your final answer would be:

$2,660

6 0
2 years ago
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Evaluate the expression when y=17 and z=7.
strojnjashka [21]
Pretty sure it would be 22.
17+7^2=66
17-2(7)=3 and you would divide 66 by 3
5 0
2 years ago
Real World Scenario:
iragen [17]

The distance of a train from the city depends on the speed, the time of

travel, and direction of motion of the train.

Correct responses:

  • Distance Train A is from the city: <u>750 - 75·t</u>
  • Distance Train B is from the city: 50·t
  • After <u>six</u> hours, the two trains are the same distance from the city
  • At that time both trains will be <u>300</u> miles away

1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours

2) At time period, t > 6 hours

3) 250 miles

<h3>Method used to find the above response</h3>

Given:

The distance of train A from the city = 750 miles

Speed of train A = 75 mph

Time at which Train B leaves the city = When Train A is 750 miles from the city

Speed of Train B = 50 mph

Solution:

The equations are;

  • Distance of Train A from the city is; <u>x₁ = 750 - 75·t</u>
  • Distance of Train B from the city is <u>x₂ = 50·t</u>

When the train are the same distance from the city, we have;

750 - 75·t = 50·t

750 = 50·t + 75·t = 125·t

Therefore;

  • t = \mathbf{\dfrac{750}{125}} = 6

The time it takes the two trains to be the same distance from the city is 6 hours.

Which gives;

  • After <u>6</u> hours, the two trains are the same distance from the city.

The distance the trains will be after 6 hours is therefore;

750 - 75 × 6 = 300

The distance of the trains from the city after 6 hours = 300 miles

Therefore, we have;

  • At that time both trains will be <u>300</u> miles away

1) The time period Train A is further from the city is before the first 6 hours elapse; <u>0 hours ≤ t < 6 hours</u>

2) The Train B is further from the city after 6 hours of its departure from the city; <u>t > 6 hours</u>

3) The distance of Train A from the city after 4 hours is given as follows;

x₁ = 750 - 75 × 4 = 450

x₁ = 450 miles

The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200

x₂ = 200 miles

Therefore;

  • The distance between the trains after 4 hours = 450 miles - 200 miles = <u>250 miles</u>

Learn more about distance and time relationship equation here:

brainly.com/question/10804931

3 0
2 years ago
Purchase price
alekssr [168]

Answer:

B - either remains the same or increases

Step-by-step explanation:

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Does this have, one solution, no solutions, or infinite solutions?
MA_775_DIABLO [31]

Answer:

Infinite

Step-by-step explanation:

Cuz i is a smart human

6 0
3 years ago
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