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8_murik_8 [283]
2 years ago
5

What are you measuring when

Chemistry
1 answer:
wariber [46]2 years ago
3 0

Answer:

B. the amount of atoms you contain

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if you where too smoke a menthol cigarette in space, would your lungs explode? some of my friends said it would
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I dont think your lung will explode
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3 years ago
If 25.8 grams of BaO dissolve in enough water to make a 212-gram solution, what is the percent by mass of the solution?
Igoryamba
The correct answer is 12.2% BaO.

The solution is found by dividing the mass of the BaO, which is 25.8 grams, by the total mass of the solution, which is 212 grams, then multiplying it by 100 to get the percentage:
\frac{25.8}{212}*(100) =12.2%
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Explain why an atom can only emit specific wavelengths of light and not every possible wavelength
ella [17]

Answer:

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3 years ago
In the activated complex for a chemical reaction, what bonds are broken and what bonds are formed?
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8 0
3 years ago
The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m
MAXImum [283]

Answer : The molecular weight of this compound is 891.10 g/mol

Explanation :  Given,

Mass of compound = 12.70 g

Mass of ethanol = 216.5 g

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=i\times T_f\times\frac{\text{Mass of compound}\times 1000}{\text{Molar mass of compound}\times \text{Mass of ethanol}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure ethanol = -117.300^oC

T_f = temperature of solution = -117.431^oC

K_f = freezing point constant of ethanol = 1.99^oC/m

i = van't hoff factor = 1   (for non-electrolyte)

m = molality

Now put all the given values in this formula, we get

(-117.300)-(-117.431)=1\times 1.99^oC/m\times \frac{12.70g\times 1000}{\text{Molar mass of compound}\times 216.5g}

\text{Molar mass of compound}=891.10g/mol

Therefore, the molecular weight of this compound is 891.10 g/mol

7 0
3 years ago
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