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Law Incorporation [45]
2 years ago
15

Simplify the following expression.x-

" alt="\frac{2}{3}" align="absmiddle" class="latex-formula"> x\frac{6}{7}
Mathematics
1 answer:
just olya [345]2 years ago
3 0

Keeping the bases and adding the exponents, the simplified expression is:

x^{\frac{4}{21}}

<h3>How to solve a product of two terms with the same base and different exponents?</h3>

We keep the bases and add the exponents.

Hence:

x^{-\frac{2}{3}} \times x^{\frac{6}{7}} = x^{-\frac{2}{3} + \frac{6}{7}} = x^{\frac{-14 + 18}{21}} = x^{\frac{4}{21}}

More can be learned about the simplification of expressions at brainly.com/question/19338732

#SPJ1

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In circle C, what is mFH?<br><br> 31°<br> 48°<br> 112°<br> 121°
natta225 [31]

we know that

The measurement of the external angle is the semi-difference of the arcs it comprises.

so

Step 1

<u>Find the measure of the arc AJ</u>

m∠BDE=\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ BE]

in this problem we have

m∠BDE=37\°

measure\ arc\ BE=38\°

substitute in the formula

37\°=\frac{1}{2} *[measure\ arc\ AJ-38\°]

74\°=[measure\ arc\ AJ-38\°]

measure\ arc\ AJ=74\°+38\°=112\°

Step 2

<u>Find the measure of the arc FH</u>

m∠FGH=\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ FH]

in this problem we have

m∠FGH=32\°

measure\ arc\ AJ=112\°

substitute in the formula

32\°=\frac{1}{2} *[112\°-measure\ arc\ FH]

64\°=[112\°-measure\ arc\ FH]

measure\ arc\ FH=112\°-64\°=48\°

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the measure of the arc FH is 48\°

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