A beam of white light goes from air into the water droplet at an incidence angle. The angle between the red (660 nm) and violet (410 nm) parts of the refracted light is 0.19°.

<h3>What is white light?</h3>

The white light is the ray coming directly from the Sun. When it strikes any glass object, an spectrum of colors with different wavelength is formed.

Given is the angle of incidence, i = 36.2°, the refractive index of water for red light is 1.331 , the refractive index of water for violet light is 1.340 and refractive index of air is 1.

Using the Snell's law, the angle of refraction of red light will be

1.331 x sin r(R) = 1 x sin 36.2

r(R) = 26.342°

Using the Snell's law, the angle of refraction of violet light will be

1.340 x sin r(R) = 1 x sin 36.2

r (V) = 26.152°

Difference in the angle of refraction of red and violet light is

r(R) - r (V) = 26.342 - 26.152 = 0.19°

Thus, the angle between the red (660 nm) and violet (410 nm) parts of the refracted light is 0.19°.

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2 years ago

What is the acceleration of a different speck of dust that is twice as far from the center of the disk?.

mariarad [96]

The acceleration of a different speck of dust is 40 m/s.

Since the radius is been given as double and angular velocity will be constant, we can calculate the centripetal acceleration as

a = (2r)ω²

If we substitute the given values of r= 2r , and ω²= 20m/s.

Then we have

$a= (2*20) = 40 m/s^2$

Therefore, acceleration of a different speck of dust is 40 m/s.

<h3>What is centripetal acceleration?</h3>

centripetal acceleration can be regarded as acceleration of a body that is traversing a circular path.

CHECK THE COMPLETE QUESTIONS;

A speck of dust on a spinning dvd has a centripetal accelera- tion of 20 m/s2.

a. what is the acceleration of a different speck of dust that is twice as far from the center of the disk?

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3 years ago