How many liters each of a 50% acid solution and a 75% acid solution must be used to produce 90 liters of a 60% acid solution? (R

Question

2 years ago

5

ound to two decimal places if necessary.)

1 answer:

elena-14-01-66 [18.8K] · Answer 1 · 2023-03-23T05:31:05+03:00

The numbers of liters that is needed is 40 liters of 25% solution and 40 liters of 65% solution.

<h3>What is the litters about?</h3>

Note that:

We take x = volume of 25% solution.

We take y = volume of 65% solution.

So, Equation of total volume:

x + y = 80

Hence the equation of amount of acid:

0.25x + 0.65y = 0.45(80)

0.25x + 0.65y = 36

Solve x + y = 80 for x.

x = 80 - y

Then Substitute into the second equation.

0.25(80 - y) + 0.65y = 36

20 - 0.25y + 0.65y = 36

0.4y = 16

y = 40

x + y = 80

x + 40 = 80

x = 40

Therefore, The numbers of liters that is needed is 40 liters of 25% solution and 40 liters of 65% solution.

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