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Sergio [31]
2 years ago
5

How many liters each of a 50% acid solution and a 75% acid solution must be used to produce 90 liters of a 60% acid solution? (R

ound to two decimal places if necessary.)
SAT
1 answer:
elena-14-01-66 [18.8K]2 years ago
8 0

The numbers of liters that is needed is 40 liters of 25% solution and 40 liters of 65% solution.

<h3>What is the litters about?</h3>

Note that:

We take x = volume of 25% solution.

We take y = volume of 65% solution.

So, Equation of total volume:

x + y = 80

Hence the equation of amount of acid:

0.25x + 0.65y = 0.45(80)

0.25x + 0.65y = 36

Solve x + y = 80 for x.

x = 80 - y

Then Substitute into the second equation.

0.25(80 - y) + 0.65y = 36

20 - 0.25y + 0.65y = 36

0.4y = 16

y = 40

x + y = 80

x + 40 = 80

x = 40

Therefore, The numbers of liters that is needed is 40 liters of 25% solution and 40 liters of 65% solution.

Learn more about liters from

brainly.com/question/17435066

#SPJ1

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<h3>What is point of the underlined word?</h3>
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The best word to replicate this meaning would be "chronically" because it is a negative word that is used to described a condition that is persistent much like the persistent fatigue of these adolescents.

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Answer:

8 quarters

Explanation:

Let's look at the ratio first off.

2 quarters: 4 dimes: 7 nickels

Let's write it in terms of money

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If we add up all the cents then we get $1.25

Then, if we divide $5 by $1.25 we get 4.

You should then multiply the original ratio by 4:

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Let's check this by turning it to money:

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Therefore your answer is 8 quarters.

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