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bija089 [108]
1 year ago
13

What type of function is represented by the table of values below?

Mathematics
1 answer:
Novay_Z [31]1 year ago
3 0

The table represents an exponential function:

f(x) = 3^x

Then the correct option is B.

<h3>What type of function is represented by the table?</h3>

Here we have the table:

x       y

1       3

2      9

3      27

4      81

5      243

You can see that each time that x increases by one unit, the value of is multiplied by 3. This is clearly an exponential function.

The function actually is:

f(x) = 3^x

Evaluating it we get:

f(1) = 3^1 = 3\\\\f(2) = 3^2 = 9\\\\f(3) = 3^3 = 27\\...

So the correct option is B, exponential.

If you want to learn more about exponential functions:

brainly.com/question/11464095

#SPJ1

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Fill in the table.<br>Input Values = 0, 2,4<br>Rule: subtract 3<br>Input<br>Output​
jarptica [38.1K]

Answer:

Input: 0, 2, 4

Output: 3, -1, 1

Step-by-step explanation:

0-3= -3

2-3= -1

4-3= 1

3 0
3 years ago
The area of the triangle formed by x− and y− intercepts of the parabola y=0.5(x−3)(x+k) is equal to 1.5 square units. Find all p
Juliette [100K]

Check the picture below.


based on the equation, if we set y = 0, we'd end up with 0 = 0.5(x-3)(x-k).

and that will give us two x-intercepts, at x = 3 and x = k.

since the triangle is made by the x-intercepts and y-intercepts, then the parabola most likely has another x-intercept on the negative side of the x-axis, as you see in the picture, so chances are "k" is a negative value.

now, notice the picture, those intercepts make a triangle with a base = 3 + k, and height = y, where "y" is on the negative side.

let's find the y-intercept by setting x = 0 now,


\bf y=0.5(x-3)(x+k)\implies y=\cfrac{1}{2}(x-3)(x+k)\implies \stackrel{\textit{setting x = 0}}{y=\cfrac{1}{2}(0-3)(0+k)} \\\\\\ y=\cfrac{1}{2}(-3)(k)\implies \boxed{y=-\cfrac{3k}{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of a triangle}}{A=\cfrac{1}{2}bh}~~ \begin{cases} b=3+k\\ h=y\\ \quad -\frac{3k}{2}\\ A=1.5\\ \qquad \frac{3}{2} \end{cases}\implies \cfrac{3}{2}=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)


\bf \cfrac{3}{2}=\cfrac{3+k}{2}\left( -\cfrac{3k}{2} \right)\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{2}}{3=\cfrac{(3+k)(-3k)}{2}}\implies 6=-9k-3k^2 \\\\\\ 6=-3(3k+k^2)\implies \cfrac{6}{-3}=3k+k^2\implies -2=3k+k^2 \\\\\\ 0=k^2+3k+2\implies 0=(k+2)(k+1)\implies k= \begin{cases} -2\\ -1 \end{cases}


now, we can plug those values on A = (1/2)bh,


\bf \stackrel{\textit{using k = -2}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-2)\left(-\cfrac{3(-2)}{2} \right)\implies A=\cfrac{1}{2}(1)(3) \\\\\\ A=\cfrac{3}{2}\implies A=1.5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{using k = -1}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-1)\left(-\cfrac{3(-1)}{2} \right) \\\\\\ A=\cfrac{1}{2}(2)\left( \cfrac{3}{2} \right)\implies A=\cfrac{3}{2}\implies A=1.5

7 0
3 years ago
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densk [106]
To answer the problem given above, divide the difference of the prices by the original price and multiply the answer by 100%. This is,
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Therefore, the percentage markup of the new car is approximately 15.42%.
7 0
3 years ago
A painting measure 40 cm by 35 cm how many squared cm does its surface cover
miskamm [114]

Answer: Its surface covers  1400 cm²

Explanation:

Since the length of painting = 40 cm

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Since we know that area of rectangle is product of dimensions.

∴ Area of painting = length × breadth

= 40 cm × 35 cm

= 1400 cm²

∴ Its surface cover  1400 cm².

8 0
3 years ago
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