Answer:
4cos4x
Step-by-step explanation:
let's use cos
amplitude=4
period=pi/2
2pi/x=pi/2
x=4
no phase shift
y=4cos4x
pic from desmos
7 1/2 pints into quarts is 3.75
Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
For this case we have the following function:
n (t) = 2400 * (5) ^ t
For n (t) = 60000 we have:
60000 = 2400 * (5) ^ t
We clear the value of t.
For this we use the logarithm:
(5) ^ t = 60000/2400
log5 ((5) ^ t) = log5 (60000/2400)
t = log5 (60000/2400)
t = 2 days
Answer:
the number of bacteria in the culture will be 60 comma 000 after:
t = 2 days
Hello!
As we can see, our a value, which would be the coefficient of 
, which determines our slope, is negative, meaning that this whole line is negative.
Furthermore, the correlation can be determined using the r value of the linear regression, which is around -0.9.
If the r value of the linear regression is close to 1 or -1, let's say around |r| > 0.8, then we can consider the regression a strong correlation, meaning that this is a strong negative correlation, which is answer choice A.
