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Likurg_2 [28]
2 years ago
7

The wall, shown above in Figure 105.1401, has an overall length that is 37’ and 8 1/4" . Three receptacle outlets are to be inst

alled in this wall. L2 is twice as long as L1 . L1 should be _____' _____''.
Mathematics
1 answer:
azamat2 years ago
5 0

Since L₂ is twice as long as L₁, the length of L₁ should be 12' and 6 3/4".

<h3>How to calculate the length (L₁)?</h3>

First of all, we would convert the value of the overall length in feet to inches as follows:

1 feet = 12 inches

37 × 8 1/4 feet = X inches

Cross-multiplying, we have:

X = 1809/4 inches.

Since L₂ is twice as long as L₁, we have:

L₂ = 2L₁

Also, the overall length is given by:

T = 2L₁ + 2L₂

T = L₂ + 2L₂

T = 3L₂

1809/4 = 3L₂

L₂ = 1809/4 × 1/3

L₂ = 1809/12

L₂ = 150.75''

L₂ = 12' and 6 3/4".

Read more on receptacle outlets here: brainly.com/question/14604591

#SPJ1

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Let m = X^2 + 3.
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The Equation in terms of m, m^2+7m+10=0

What is substituting in the equation ?

substituting means changing or replacing the values in the given equation.

Calculation:

Given equation is (x^2+3)^2+7x^2+21=-10

            and m= X^2 + 3.

make the given equation in the form X^2 + 3,

             now,

                     (x^2+3)^2+7x^2+21=-10

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             we get, m^2+7m=-10

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The Equation in terms of m, m^2+7m+10=0

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2 years ago
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