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2 years ago

Using the addition or subtraction formulas for sine or cosine.... sinasinb=(cos(a-b)-cos(a+b))/2

Mathematics

1 answer:

raketka [301]2 years ago

7 0

Answer:

The answer w'll be obtained using formulas

cos(a+b) = cosacosb - sinasinb

cos(a-b) = cosacosb + sinasinb

Step-by-step explanation:

Using the trigonometric formula of addition and subtraction of cosine

cos(a+b) = cosacosb - sinasinb

cos(a-b) = cosacosb + sinasinb

w'll get the desired answer.

To be solve

L.H.S = R.H.S

sinasinb = (cos(a-b)-cos(a+b)/2

as we know that cos(a+b) = cosacosb - sinasinb

sinasinb = (cos(a-b) - (cosacosb -sinasinb))/2

as we know that cos(a-b) = cosacosb + sinasinb

sinasinb = ((cosacosb + sinasinb) - (cosacosb -sinasinb))/2

sinasinb = (cosacosb + sinasinb - cosacosb + sinasinb)/2

sinasinb = (2sinasinb)/2

sinasinb = sinasinb

hence L.H.S = R.H.S

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3 years ago

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Answer:

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3 years ago

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emmainna [20.7K]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers