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1 year ago

6

Prove that cos1° cos2° cos3°...cos180° = 0

1 answer:

leva [86]1 year ago

4 0

Answer:

I don't know‍♀ sorrry bro

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A church has 8 bells in its bell tower. Before each church service 5 bells are rung in sequence. No bell is rung more than once.

Basile [38]

Use the ! tool to find the # of combinations.

8!/5! = 40,320/120 = 336

8 0

3 years ago

Read 2 more answers

Lines g,h and l are parallel and m< 2 = 129<br> What is the m < L

Bingel [31]

180-129= 51
angle 4 is equal to angle 12 so missing angle 12= 51°

6 0

3 years ago

The space shuttle discovery was retired in spring thousand and 12 discovery was first launched in 1984 and flu over 149,000,000

Rina8888 [55]

Answer:

it would be about 5984 times around the earth

Step-by-step explanation:

first of all 149,000,000 miles is active lifetime

Using those measurements, the equatorial circumference of Earth is about 24,901 miles

so therefore if you divide 149,000,000 by 24,901 you would get the answer of 5983.69543392 so if you round all the numbers to the nearest whole number you would get 5984

hope tis helps out with your question

5 0

2 years ago

Please solve this fast

Korolek [52]

Step-by-step explanation:

1.

$qr - pr \: + qs - ps$

$r(q - p) + s(q - p)$

$(r + s)(q - p)$

2.

${x}^{2} + y - xy - x$

${x}^{2} - x - xy + y$

$x(x - 1) - y(x - 1)$

3.

$6xy + 6 - 9y - 4x$

$- 4x + 6 + 6xy - 9y$

$2( - 2x + 3) - 3y( - 2x + 3)$

$(2 - 3y)( - 2x + 3)$

4.

${x}^{2} - 2ax - 2ab + bx$

$x(x - 2a) - b(x - 2a)$

$-(x +b)(2a-x)$

5.

$axy + bcxy - az - bcz$

$xy(a + bc) - z(a + bc)$

$(xy - z)(a + bc)$

3 0

2 years ago

Read 2 more answers

A large company put out an advertisement in a magazine for a job opening. The first day the magazine was published the company g

Evgen [1.6K]

Answer:

16 responses

Step-by-step explanation:

we know that

A geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.

$a_n=r^{n-1}$

where

a_n----> $n^{th}$ term of the sequence

r ---> is the common ratio

a ---> the first term of the sequence

$a=50\\r=100\%-10\%=90\%=90/100=0.90$

substitute

$a_n=50(0.90)^{n-1}$

For n=12

substitute

$a_n=50(0.90)^{12-1}=16$

3 0

3 years ago