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Dafna1 [17]
3 years ago
9

What is the interquartile range of this data set 2, 5, 9, 11, 18, 30, 42, 48, 71, 73, 81

Mathematics
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer:

I believe the answer is 62.

Step-by-step explanation:

Hope my answer has helped you!

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In roulette, you may bet whether the number that comes up is odd (or even). (Remember that 0 and 00 do not count as either odd o
EastWind [94]

Answer: - 0.027

Step-by-step explanation:

Win = any even number between (0 - 36)

Therefore,

Lose = any odd number between 0 —36 including 0

Assume Bet amount = $1

Expected value is calculate by summing all possible outcomes by their respective probabilities.

Expected value = [(p(winning) × net win value) + (p(losing +net loss value]

P(winning) = p(even) = 18/37

P(losing) = p(odd) +p(0) = 19/37

Net win value = $2

Net loss value = $-1

Expected value = [(18/37) × ($1) + (19/37) × (-$1)]

Expected value = 0.48648648 - 0.51351351

Expected value = - 0.027

7 0
3 years ago
Please help I don’t understand how to do these
steposvetlana [31]

Answer:

I think there would be 86 blue marbles

x=4(106 - x ) + 6

x= 424 - 4x + 6

5x= 430

x= 86 blue marbles

Tell me if I'm wrong, hope this helps.

3 0
3 years ago
How many centimeters are in 8 meters?
Law Incorporation [45]

Answer:

800 centimeters.......

3 0
2 years ago
Please please help me!!!!!
Tamiku [17]
Your just multiplying 7 and 10, so your answer is gonna be B.
6 0
3 years ago
Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
10 months ago
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