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Olegator [25]
2 years ago
8

Use the Associative Property to find the value of the variable. (8 x 15) x s = 8 x (15 x 11)

Mathematics
1 answer:
kvasek [131]2 years ago
5 0

Answer:

hey its me again so the answer is 11.

I'm sure because I did this.

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27 bikini styles and 63 other types of swimsuit. What percentage of the swimsuit styles are bikinis?
Elis [28]


27/63= .4285

Which is the answer

3 0
3 years ago
How can i solve the equation 4(2x+7)
myrzilka [38]
Distribute so times what's outside by what's inside so 4×2x=8x and 4×7=28 then get x by itself by dividing on both sides 28÷8=3.5 your answer is x=3.5
3 0
3 years ago
Read 2 more answers
For each hour he babysit,Anderson earns 1$ more than half of carey's hourly rate.Anderson earns 6$ per hour. wich equation can b
Lena [83]

Answer:

The expression to find Carey's hourly rate is: c = 2*a - 2. Carey's hourly rate is $10.

Step-by-step explanation:

Anderson receives 1 more than half of carey's hourly rate. If we call Anderson's rate by "a" and Carey's by "c", we can express this phrase in the following equation:

a = \frac{c}{2} + 1

We want to find the Carey's rate, therefore we need to isolate the "c" variable.

\frac{c}{2} + 1 = a\\\frac{c}{2} = a - 1\\c = 2*a - 2

Since Anderson earns $6, then we can find Carey's rate:

c =  2*6 - 2 = 12 - 2 = 10

6 0
3 years ago
Solve the equation for<br> x 3/4(x+21) = 10.5 <br> x =
MrRa [10]
<h3>✍️ Answer:</h3><h3>x=-\frac{294}{13}</h3>

✽✽✽✽

\frac{x\cdot \:3}{4\left(x+21\right)}=10.5

\mathrm{Multiply\:both\:sides\:by\:}4\left(x+21\right)

\frac{x\cdot \:3}{4\left(x+21\right)}\cdot \:4\left(x+21\right)=10.5\cdot \:4\left(x+21\right)

3x=42\left(x+21\right)

3x=42x+882

\mathrm{Subtract\:}42x\mathrm{\:from\:both\:sides}

3x-42x=42x+882-42x

-39x=882

\mathrm{Divide\:both\:sides\:by\:}-39

\frac{-39x}{-39}=\frac{882}{-39}

x=-\frac{294}{13}

❅❅❅❅❅❅❅❅❅❅

<h3>hope it helps...</h3><h3>have a great day!!</h3>
4 0
3 years ago
Which of the following best defines a function?
Sidana [21]
Answer: <span>A. A function is a special type of relation for which there is a rule that pairs each input with exactly one output.

Option B is incorrect because it does not include that there cannot be two x-values with the same y-value. Option C is incorrect because it is a relation, not just a set of ordered pairs. Option D is incorrect because there <em>is</em> a particular pattern in a function.

Hope this helps!</span>
8 0
3 years ago
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