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Kay [80]
2 years ago
9

The value of y is directly proportional to the value of x.If y=12 when x=9, what is the value of x when y=80

Mathematics
1 answer:
Simora [160]2 years ago
7 0

Step 1:

Write the formula connecting y and x.

\begin{gathered} y\text{ }\propto\text{   x} \\ y\text{ = kx} \\ k\text{ = }\frac{y}{x} \end{gathered}

Step 2:

Find the value of k when y = 12 and x = 9

\begin{gathered} k\text{ = }\frac{y}{x}\text{  =  }\frac{12}{9}\text{   =  }\frac{4}{3} \\ \text{Therefore} \\ y\text{ = }\frac{4}{3}x \end{gathered}

Step 3

You can find x when y = 80.

\begin{gathered} \text{Frpm y = }\frac{4}{3} \\ \text{When y = 80} \\ 80\text{ = }\frac{4x}{3} \\ \text{Cross multiply} \\ 4x\text{ = 80}\times3 \\ 4x\text{ = 240     Divide both sides of the equation by 4} \\ x\text{ = }\frac{240}{4} \\ x\text{ = 60} \end{gathered}

Final answer

x = 60

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1 solution

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3 years ago
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What is the quotient of -8a^8b^-2/10a^-4b^-10 in simplified form? Assume a=0 b=0 A.) -4a^12b^8/5 B.)-4a^32b^5/5 C.)a^12b^8/80 D.
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