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dem82 [27]
2 years ago
7

Which of the following is an exponential function y=x^1/2 y=2x^3 y=3^x

Mathematics
1 answer:
Sveta_85 [38]2 years ago
8 0

Answer:

  (c)  y = 3^x

Step-by-step explanation:

A function is described as exponential if the independent variable is found in the exponent.

<h3>Choices</h3>

  y = x^(1/2) . . . a square root function, not exponential

  y = 2x^3 . . . . a cubic (polynomial) function, not exponential

  y = 3^x . . . . . an exponential function

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Generate the nest three terms of each arithmetic sequence shown below.
o-na [289]

Answer:

A)2,6,10

B)2,-6,-18

C)-1,-3,-5

Step-by-step explanation:

<u>A)a1=-2 and d=4</u>

We know that the arithmetic sequence formula is

a_{n}=a_{1}+(n-1)d

Now

a_{2}=a_{1}+(2-1)d

a_{2}=a_{1}+(1)d

Substituting the given value we get

a_{2}= -2+(1)4

a_{2}= -2+4

a_{2}= 2

------------------------------------------

Similarly

a_{3}=a_{1}+(3-1)d

a_{3}=a_{1}+(2)d

Substituting the given value we get

a_{3}= -2+(2)4

a_{3}= -2+8

a_{3}= 6

-------------------------------------------------

a_{4}=a_{1}+(4-1)d

a_{4}=a_{1}+(3)d

Substituting the given value we get

a_{4}= -2+(3)4

a_{4}= -2+16

a_{4}= 10

-------------------------------------------------------------------------------------------

<u>B</u><u>  a_n=a_{(n-1)}-8  with a_1=10</u>

a_2=a_{(2-1)}-8

a_2=a_{1}-8

Substituting the given value

a_2= 10-8

a_2=2

---------------------------------------------------------------------

a_3=a_{(3-1)}-8

a_3=a_{2}-8

Substituting the  value

a_3=2-8

a_3= -6

---------------------------------------------------------------------

a_4=a_{(4-1)}-8

a_4=a_{3}-8

Substituting the  value

a_4= -6-8

a_4= -14

-------------------------------------------------------------------------------------------

<u>C) a_1=3, a_2=1</u>

Here the difference is -2

the arithmetic sequence formula is

a_{n}=a_{1}+(n-1)d

Now

a_{3}=a_{1}+(3-1)d

a_{3}=a_{1}+(2)d

Substituting the value we get

a_{3}= 3+(2)-2

a_{3}= 3-4

a_{3}= -1

------------------------------------------------------------------------------

a_{4}=a_{1}+(4-1)d

a_{4}=a_{1}+(3)d

Substituting the value we get

a_{4}= 3+(3)-2

a_{4}= 3-6

a_{4}= -3

----------------------------------------------------------------------------------

a_{5}=a_{1}+(5-1)d

a_{5}=a_{1}+(4)d

Substituting the value we get

a_{5}= 3+(4)-2

a_{5}= 3-8

a_{5}= -5

4 0
3 years ago
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