<h3>
Answer: 3x^3 + 11x^2 - 5x - 25</h3>
Work Shown:
yz = y(x^2+2x-5)
yz = y(x^2) + y(2x) + y(-5)
yz = x^2( y ) + 2x( y ) - 5( y )
yz = x^2( 3x+5 ) + 2x( 3x+5 ) - 5( 3x+5 )
yz = x^2*3x + x^2*5 + 2x*3x + 2x*5 - 5*3x - 5*5
yz = 3x^3 + 5x^2 + 6x^2 + 10x - 15x - 25
yz = 3x^3 + 11x^2 - 5x - 25
The correct number of servings would be = 12/25
<h3>What is a cooking class?</h3>
A cooking class is defined as the class that is made up of students that are being thought how to prepare and serve different types of food.
The total amount of quarts of food made by the students = 4½.
The number of servings to friends = ⅘
The quantity of quarts in each serving = ⅗ quarts
Total number of quarts served = ⅘ × ⅗= 12/25
The correct number of servings = 12/25
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Two halfs equal one whole. think of it like this, an orange cut in half leaves you with two halfs, put them together and you have a whole. simple. multiplying by 2 just means adding a number two times.
1 half plus one half= 2halves= 1 whole
1half x 2= 2 halves=1 whole
The summation of the considered expression in terms of n from n = 1 to 14 is given by: Option D: 343
<h3>How to find the sum of consecutive integers?</h3>
<h3>
What are the properties of summation?</h3>
![\sum_{i=r}^s (a \times f(i) + b) = a \times [\: \sum_{i=r}^s f(i)] + (s-r)b](https://tex.z-dn.net/?f=%5Csum_%7Bi%3Dr%7D%5Es%20%20%28a%20%5Ctimes%20f%28i%29%20%2B%20b%29%20%3D%20a%20%5Ctimes%20%5B%5C%3A%20%5Csum_%7Bi%3Dr%7D%5Es%20f%28i%29%5D%20%2B%20%28s-r%29b)
where a, b, r, and s are constants, f(i) is function of i, i ranging from r to s (integral assuming).
For the given case, the considered summation can be written symbolically as:
It is evaluated as;
![\sum_{n=1}^{14} (3n + 2) = 3 \times [ \: \sum_{n=1}^{14} n ] + \sum_{n=1}^{14} 2\\\\\sum_{n=1}^{14} (3n + 2) = 3 \times \dfrac{(14)(14 + 1)}{2} + (2 + 2 + .. + 2(\text{14 times}))\\\\\sum_{n=1}^{14} (3n + 2) = 3 \times 105 + 28 = 343\\](https://tex.z-dn.net/?f=%5Csum_%7Bn%3D1%7D%5E%7B14%7D%20%20%283n%20%2B%202%29%20%3D%203%20%5Ctimes%20%5B%20%5C%3A%20%5Csum_%7Bn%3D1%7D%5E%7B14%7D%20n%20%5D%20%2B%20%5Csum_%7Bn%3D1%7D%5E%7B14%7D%202%5C%5C%5C%5C%5Csum_%7Bn%3D1%7D%5E%7B14%7D%20%20%283n%20%2B%202%29%20%3D%203%20%5Ctimes%20%5Cdfrac%7B%2814%29%2814%20%2B%201%29%7D%7B2%7D%20%2B%20%282%20%2B%202%20%2B%20..%20%2B%202%28%5Ctext%7B14%20times%7D%29%29%5C%5C%5C%5C%5Csum_%7Bn%3D1%7D%5E%7B14%7D%20%20%283n%20%2B%202%29%20%3D%203%20%5Ctimes%20105%20%2B%2028%20%3D%20343%5C%5C)
Thus, the summation of the considered expression in terms of n from n = 1 to 14 is given by: Option D: 343
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Answer:
Step-by-step explanation:
A=P(1+rt)
A=200(1+.02(3))
A=200(1.06)
A=$212
