Hello, may I please get help with (7x-3)+(-7x+3)?

1. Find the standard form of the equation of the parabola with a focus at (0, -9) and a directrix y = 9.

Rasek [7]

Answer:

Part 1) Option C) y = negative one divided by thirty six x²

Part 2) Option A) y = one divided by thirty six x²

Part 3) Vertex: (0, 0); Focus: one divided by sixteen comma zero; Directrix: x = negative one divided by sixteen; Focal width: 0.25

Part 4) Option C) x = one divided by twelve y²

Step-by-step explanation:

Part 1) Find the standard form of the equation of the parabola with a focus at (0, -9) and a directrix y = 9.

we know that

The vertex form of the equation of the vertical parabola is equal to

$(x-h)^{2}=4p(y-k)$

where

Vertex ----> (h,k)

Focus ----> F(h,k+p)

directrix -----> y=k-p

we have

F(0,-9)

so

h=0

k+p=-9 -----> equation A

y=9

so

k-p=9 ----> equation B

Adds equation A and equation B

k+p=-9

k-p=9

-----------

2k=0

k=0

so

Find the value of p

0+p=-9

p=-9

substitute in the equation

$(x-0)^{2}=4(-9)(y-0)$

$(x)^{2}=-36y$

Convert to standard form

isolate the variable y

$y=-\frac{1}{36}x^{2}$

Part 2) Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, 9)

we know that

The vertex form of the equation of the vertical parabola is equal to

$(x-h)^{2}=4p(y-k)$

where

Vertex ----> (h,k)

Focus ----> F(h,k+p)

directrix -----> y=k-p

we have

Vertex (0,0) -----> h=0,k=0

F(0,9)

so

k+p=9------> 0+p=9 -----> p=9

substitute in the equation

$(x-0)^{2}=4(9)(y-0)$

$(x)^{2}=36(y)$

Convert to standard form

isolate the variable y

$y=\frac{1}{36}x^{2}$

Part 3) Find the vertex, focus, directrix, and focal width of the parabola.

x = 4y²

we know that

The vertex form of the equation of the horizontal parabola is equal to

$(y-k)^{2}=4p(x-h)$

where

Vertex ----> (h,k)

Focus ----> F(h+p,k)

directrix -----> x=h-p

we have

$x=4y^{2}$ -----> $y^{2}=(1/4)x$

so

Vertex (0,0) ------> h=0,k=0

4p=1/4 ------> Focal width

p=1/16

Focus F(0+1/16,0) ----> F(1/16,0)

directrix -----> x=0-1/16 -----> x=-1/16

therefore

Vertex: (0, 0); Focus: one divided by sixteen comma zero; Directrix: x = negative one divided by sixteen; Focal width: 0.25

Part 4) Find the standard form of the equation of the parabola with a focus at (3, 0) and a directrix at x = -3.

we know that

The vertex form of the equation of the horizontal parabola is equal to

$(y-k)^{2}=4p(x-h)$

where

Vertex ----> (h,k)

Focus ----> F(h+p,k)

directrix -----> x=h-p

we have

Focus F(3,0)

so

h+p=3 ------> equation A

k=0

directrix x=-3

so

h-p=-3 ------> equation B

Adds equation A and equation B and solve for h

h+p=3

h-p=-3

------------

2h=0 -----> h=0

Find the value of p

h+p=3 ------> 0+p=3 ------> p=3

substitute in the equation

$(y-0)^{2}=4(3)(x-0)$

$(y)^{2}=12(x-0)$

Convert to standard form

isolate the variable x

$x=\frac{1}{12}y^{2}$

4 0

4 years ago

3 (40 - 2) + 5 = 12a - 1

Rom4ik [11]

Answer:

a = 5.5

Step-by-step explanation:

3 (40 - 2) + 5 = 12a - 1

120 - 60 + 5 = 12a - 1

60 + 5 = 12a - 1

65 = 12a - 1

+1 +1

66 = 12a

/12 /12

5.5 = a

a = 5.5

3 0

3 years ago

(pythagoras theorem | year9)

viktelen [127]

answer is in the picture, hope this helps ^-^

3 0

3 years ago

Jamie Rented a jetski. It costs 25$ to rent the boat plus $5.50 per hour. He also rents y number of life jackets for $6 each. Ho

gulaghasi [49]

Answer:

200-25= 175

175/35= 5 hours

Step-by-step explanation:

Hope it helps

8 0

3 years ago

Dan has a board that is

Strike441 [17]

Answer:

He is wrong.
The answer is 3 11/12.

Step-by-step explanation:

Given equation:

8 3/4 - 4 5/6

Simplify:

8 9/12 - 4 10/12

Solve:

8 - 4 = 4
= 9/12 - 10/12
= 21/12 - 10/12
= 11/12
= 3 + 11/12
= 3 11/12.

He is wrong.

He was off by 3 digits.

5 0

2 years ago