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3 years ago

3 (40 - 2) + 5 = 12a - 1

Mathematics

1 answer:

Rom4ik [11]3 years ago

3 0

Answer:

a = 5.5

Step-by-step explanation:

3 (40 - 2) + 5 = 12a - 1

120 - 60 + 5 = 12a - 1

60 + 5 = 12a - 1

65 = 12a - 1

66 = 12a

5.5 = a

a = 5.5

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Step-by-step explanation:

if the function is f(x) and shes already saved $1000 plug in the functions, or in other words plug in x for weeks.

1000 + 150 x

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1000 + 150 x 12

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then add how muh shes saved and thats will be your total.

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The two traingles, VSU and TSR are similar by SAS similarity criteria.

According to the diagram,
UT = TS
and
VR = SR

$\frac{ST}{SU} = \frac{ST}{ST + SU} \\ = \frac{ST}{2ST} = \frac{1}{2}$

Similarly for all sides the ratio must be same.
Applying this on the side required here,

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3 years ago

What is the equation of the line of best fit for the following data? Round the

Svet_ta [14]

Answer:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=438-\frac{44^2}{5}=50.8$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=415-\frac{44*42}{5}=45.4$

And the slope would be:

$m=\frac{45.4}{50.8}=0.8937 \approx 0.894$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{44}{5}=8.8$

$\bar y= \frac{\sum y_i}{n}=\frac{42}{5}=8.4$

And we can find the intercept using this:

$b=\bar y -m \bar x=8.4-(0.894*8.8)=0.535$

So the line would be given by:

$y=0.894 x +0.535$

And the best option is:

A. y = 0.894x + 0.535

Step-by-step explanation:

We have the following dataset given

x: 5,6,9,10,14

y: 4,6,9,11,12

We want to find the least-squares line appropriate for this data given by this general expresion:

$y = mx +b$

Where m is the slope and b the intercept

For this case we need to calculate the slope with the following formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

So we can find the sums like this:

$\sum_{i=1}^n x_i = 44$

$\sum_{i=1}^n y_i =42$

$\sum_{i=1}^n x^2_i =438$

$\sum_{i=1}^n y^2_i =398$

$\sum_{i=1}^n x_i y_i =415$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=438-\frac{44^2}{5}=50.8$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=415-\frac{44*42}{5}=45.4$

And the slope would be:

$m=\frac{45.4}{50.8}=0.8937 \approx 0.894$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{44}{5}=8.8$

$\bar y= \frac{\sum y_i}{n}=\frac{42}{5}=8.4$

And we can find the intercept using this:

$b=\bar y -m \bar x=8.4-(0.894*8.8)=0.535$

So the line would be given by:

$y=0.894 x +0.535$

And the best option is:

A. y = 0.894x + 0.535

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