ANSWER:
Domain: {3, 7, 4, a}
Range: {a, b, 4, 0}
Easiest way is if you substitute each point (x,y) into each set of equations and both points work for both equations in the system of equations, then it is the correct answer
Otherwise substitute one equation for y in the other equation:
2x + 6 = x^2 + 5x + 6
-2x - 6. -2x -6
0 = x^2 + 3x. Factor
0 = x (x + 3)
Solve: x = 0. x + 3 = 0. ——> x = -3. Substitute into one original equation to get y value for
y = 2x + 6.
y = 2(0) + 6. y = 2(-3) + 6
y = 6. y = -6 + 6 —-> y = 0
(0 , 6) And. (-3 , 0)
Answer:
89m
Step-by-step explanation:
First, find the area of the rectangle (ignoring the missing triangle inside). The area of the rectangle is its base times its height, which is 8*13=104.
Next, find the area of the triangle. The area of the triangle is its base times height, divided by two.
The width of one side of the rectangle is 13, and the width of the side of the rectangle is 8 (4 + 4). Therefore, subtract 8 from 13 and the missing section in the side of the rectangle is 5. 5 is equal to the base of the triangle.
The height of the triangle is given, which is 6. As stated before, the area of a triangle is its base times height divided by two, which is 5*6/2 in this case. The area of the triangle is equal to 15.
Now, subtract the area of the triangle from the area of the rectangle. 104-15=89.
Answer:
The digit that is in the TENS place is 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
To find the area subtract the area of the semicircle from the area of the rectangle.
Although the line isn’t there, if you imagine there is one, then you will see that you form a rectangle which is the same line as the semicircle’s diameter.
The area of rectangle is:
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The area of the semicircle;
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*Note here that the radius is half the diameter, so it is 7cm, not 14cm
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Finally subtract the two areas;
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