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4vir4ik [10]
3 years ago
6

The diagonals of a rhombus are _____

Mathematics
1 answer:
Basile [38]3 years ago
3 0

Answer:

Negative reciprocals

Step-by-step explanation:

When proving a quadrilateral is a function you can tell it is true if diagonal sides are negative reciprocals of each other

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Find the number of trucks for 128 vehicles... table shown above
WARRIOR [948]

Answer:

48

Step-by-step explanation:

it is 48 because you divide 128 by the number of vehicles and then you multiply that number you get (16) by the number of trucks and there you go 48 :)

4 0
3 years ago
Please help me! Due Thursday!
REY [17]

Answer:

is c

Step-by-step explanation:

4 0
3 years ago
How do you solve<br> -6n-20=-2n+4 (1-3n)
DedPeter [7]
-6n-20=-2n+4-12n
-6n-20=-14n+4
+6n       +6n
-20=-8n+4
-4          -4
-24=-8n
/8     /8
n=-3
         -
3 0
3 years ago
At any point in time, there could be bicycles, tricycles, and
Aleksandr-060686 [28]

Answer:

There may be 1 or 3 tricycles in the parking lot.

Step-by-step explanation:

Since at any point in time, there could be bicycles, tricycles, and cars in the school parking lot, and today, there are 53 wheels in total, if there are 15 bicycles, tricycles, and cars in total, to determine how many tricycles could be in the parking lot, the following calculation must be performed:

13 x 4 + 1 x 3 + 1 x 2 = 57

11 x 4 + 1 x 3 + 3 x 2 = 53

10 x 4 + 3 x 3 + 2 x 2 = 53

8 x 4 + 5 x 3 + 2 x 2 = 51

10 x 2 + 1 x 3 + 4 x 4 = 39

9 x 3 + 1 x 2 + 5 x 4 = 49

Therefore, there may be 1 or 3 tricycles in the parking lot.

6 0
3 years ago
In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
2 years ago
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