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Natali5045456 [20]
2 years ago
10

Type the correct answer in the box.

Mathematics
1 answer:
Kay [80]2 years ago
4 0

The surface area of this three-dimensional figure is equal to 536.6 square centimeters.

<h3>How to determine the surface area?</h3>

First of all, we would determine the total area of the three rectangles by using this formula:

Total area = 3 × Length × Width

Total area = 3 × 15 × 10

Total area = 450 cm².

Next, we would determine the total area of the two triangles by using this formula:

Total area = 2 × (1/2 × b × h)

Total area = b × h

Total area = 8.66 × 10

Total area = 86.6 cm².

Surface area = 450 + 86.6

Surface area = 536.6 cm².

Read more on rectangle here: brainly.com/question/25292087

#SPJ1

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A jar contains black marbles and green marbles. Sixty percent of the marbles in the jar are green. A number generator simulates
Natali5045456 [20]

Answer:

The number generator is not fair. In most of the experiments, considerably less than 60% of the selected marbles are green.

Step-by-step explanation:

Run a significant number of times, a fair distribution should be a bell curve  centered on the 6 for 60%

7 0
2 years ago
A. Identify the percentage, rate and base.
Finger [1]

Answer:

1. rate = 30, base = 40, percentage = 12

2. rate = 6, base = 24, percentage = 25

3. rate = 16, base = 64, percentage = 25

4. rate = 4, base = 50, percentage = 20

5. rate = 75, base = 80, percentage = 60

Step-by-step explanation:

5 0
3 years ago
Use the figure to decide the type of angle pair that describes 6 and 4
kumpel [21]
It’s corresponding angles
3 0
3 years ago
Are is the Triangle SWT and triangle SVU similar? What would be the answer?
kondaur [170]

Answer:

A) Yes the 2 triangles are similar by SSS Similarity and SAS Similarity

Step-by-step explanation:

SSS:

ST/SU = SW/SV = WT/VU

60/70 = 48/56 = 30/35

6/7 = 6/7 = 6/7

SAS:

ST/SU = SW/SV = 6/7 (look at SSS proving)

Angle S = Angle S because they are reflexive or the same angles

4 0
3 years ago
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
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