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ss7ja [257]
3 years ago
13

I need help with a question

Mathematics
1 answer:
kondaur [170]3 years ago
5 0
What question do you need help with
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What is the alternating sum of digits
Morgarella [4.7K]

Answer:Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11. Since -11 is divisible by 11, so is 2728.

Hope this helped

6 0
3 years ago
Factor x2 + 29x + 120
CaHeK987 [17]

Answer:

(x+5)(x+24)

Step-by-step explanation:

5 0
3 years ago
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What is x if x+85=x+105
vaieri [72.5K]

Answer:x+85=x+105

x+x=105+85

2x=190

x=190/2

x=95

Step-by-step explanation:

4 0
3 years ago
Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab
Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

Since simplified left and right parts are the same, then the equality is true.

3 0
3 years ago
Can you please help with this math?&gt;&gt;
goblinko [34]

x = 16 x sin(60) = 8sqrt(3)

 answer is B.

6 0
3 years ago
Read 2 more answers
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