Which image shows triangle ABC dilated by a scale factor of 3 centered at the point B
1 answer:
If triangle ABC undergoes a dilation of scale factor 3 centered at the origin, the coordinate of the image of point B is known to be option D. (6,9).
<h3>What is the dilation about?</h3>The term Dilation is known to be a kind of a transformation, that is used to change the size of an object.
Note that Point B has coordinates of (2, 3)
So the Dilation factor 3 will alter the coordinates as:
(2*3, 3*3)
= (6, 9)
Hence, If triangle ABC undergoes a dilation of scale factor 3 centered at the origin, the coordinate of the image of point B is known to be option D. (6,9).
See full question below
If triangle ABC undergoes a dilation of scale factor 3 centered at the origin, what will be the coordinate of the image of point B?
A. (6,3)
B. (2,9)
C. (5,6)
D. (6,9)
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There are different ways to model real life grade scenario. An example is Numerical Expressions and Factors.
An example is: create a Venn diagram that represents the prime factorizations of 36 and 48.
<h3>What is Big Ideas Math 6 Book about?</h3>They are known to be a form of well organized and lucidly explained text about mathematics that is aimed towards students. They are made up of tests, quizzes, assessments and others.
The Venn diagram that represents the prime factorizations of 36 and 48 is in the image attached.
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<h3>Answer:</h3>
60 days
<h3>Explanation:</h3>Half-life is the amount of time it takes half of a substance to decay away.
Guess and Check
One method for solving half-life problems like this is to guess and check. To do this, we can continue to divide 475mg by 2 until we get to 30mg.
- 475 ÷ 2 = 237.5
- 237.5 ÷ 2 = 118.75
- 118.75 ÷ 2 = 59.375
- 59.375 ÷ 2 = 29.6875
As seen here, it takes approximately 4 half-lives for this sample of Ra-225 to decay to 30mg. Now, we can multiply 4 by the length of the half-life, 15 days.
- 4 * 15 = 60 days.
Fractions
Another way to solve this is to use fractions.
- 30 is about 1/16 of 475
- 16 is equivalent to
.
This means that it takes 4 half-lives for 475mg to decay to 30mg. Using the same method above, we can tell that 4 half-lives are 60 days.
Important Note
In this question, I rounded occasionally. So, not all of the values are exact, but they are all very close.