Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
I'm sorry ninth grade slow learner
Sizes? Of the wall and paper?
The solved inequality is t > 12.
Divide both sides by 9 to isolate the variable.
9t becomes t, and 108 becomes 12.
<u>We do not flip the sign because we are dividing by a </u><u>positive</u><u>.</u>
Answer:
Circ=37.704, Area= 112.112
Step-by-step explanation:
Circumference= pi *Diameter
Taking pi=3.142, Diameter=12
Circ=3.142*12=37.704
Area= pi * r^2
Area= 3.142*6*6=112.112