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Shkiper50 [21]
3 years ago
13

11. Give the solution to: ^64+8² ​

Mathematics
1 answer:
stellarik [79]3 years ago
8 0

Answer:

128 (character filter filler here)

Step-by-step explanation:

64+8^2 is 128

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Can somebody please help me with this
Paul [167]

<em>∠PYG = 137°</em>

Step-by-step explanation:

We know that a straight line is equal to 180°, so by looking at the image we can tell that if we added both of these angles together they would be equal to the straight line.

We can make an equation by adding these two angles together and setting them equal to 180.

2p+153+6p+91=180

We can combine like terms.

8p+244=180

Subtract 244 from both sides.

8p=-64

Divide.

<em><u>p = -8</u></em>

Now that we have found what p is equal to, we can plug it in to find the measure of ∠PYG.

2*-8+153

<em><u>= 137</u></em>

~

If you wanted to double check this answer, we can plug in -8 for p on the other side and make sure both would be equal to 180.

Like this...

6*-8+91

= 43

And we know that...

137 + 43 = 180

~

So...

<u><em>∠PYG = 137°</em></u>

<u><em>∠HYG = 43°</em></u>

4 0
3 years ago
Christian can paint a car in 6 hours. Carter can paint the same car in 3 hours. If they work together, how long will it take to
just olya [345]
It would take them 2 hours to paint the whole car

5 0
3 years ago
Read 2 more answers
Simplify surds √50+√√72-√√128​
34kurt

Answer:

3\sqrt{2}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplify the given radicals

\sqrt{50}

= \sqrt{25(2)}

= \sqrt{25} × \sqrt{2}

= 5\sqrt{2}

------------------------

\sqrt{72}

= \sqrt{36(2)}

= \sqrt{36} × \sqrt{2}

= 6\sqrt{2}

-----------------------

\sqrt{128}

= \sqrt{64(2)}

= \sqrt{64} × \sqrt{2}

= 8\sqrt{2}

Then

\sqrt{50} + \sqrt{72} - \sqrt{128}

= 5\sqrt{2} + 6\sqrt{2} - 8\sqrt{2}

= 11\sqrt{2} - 8\sqrt{2}

= 3\sqrt{2}

3 0
3 years ago
Find the GCF. 18x 3 and 30x 5 A. 6x 5 B. 90x 3 C. 6x 3 D. 90x 5
muminat
<span>GCF. 18x^3 and 30x^5 = 6x^3

answer is </span><span>C. 6x^3</span>
8 0
3 years ago
Which is the equation of the circle that has a diameter with endpoints located at (-2, 0) and (6, 6)?
Tpy6a [65]
(x-2)^2 + (y-3)^2 = 25


center is 2,3
diameter is 10
rad is 10/2 = 5


Mark brainliest please
5 0
3 years ago
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