All categories

2 years ago

Deeksha made cuboid of size 2 cm x 3 cm x 4 cm. how many such

Mathematics

1 answer:

faltersainse [42]2 years ago

4 0

The number of cuboids of dimension 2 cm x 3 cm x 4 cm, required to make a cube is <u>9</u>.

Dimensions of the cuboid Deeksha made are given as 2 cm x 3 cm x 4 cm.

Thus, the volume of this cuboid = 2*3*4 cm³ = 24 cm³.

Using the formula for the volume of cuboid as the product of the three sides.

Deeksha wants to make a cube combining some number of these cuboids.

Assuming the side length of the cube to a, the volume of the cube = a³.

Assuming the number of cuboids required to make 1 cube to be n, we can write that a³ = n*(24 cm³).

To make this relation true, we need the right-hand side to be a perfect cube.

Prime factorizing the volume of the cuboid, we get 24 cm³ = 2³ * 3 cm³.

To make it a perfect cube, we need to multiply 3², by it.

Thus, n = 3² = 9.

Thus, the number of cuboids of dimension 2 cm x 3 cm x 4 cm, required to make a cube is <u>9</u>.

Learn more about cubes and cuboids at

brainly.com/question/12888603

#SPJ4

The provided question is incorrect. The correct question is:

"Deeksha made cuboid of size 2 cm x 3 cm x 4 cm. how many such

cuboids will be required to make a cube?"

You might be interested in

The roof of the building shown below has a span of 48 feet. The rafters upon which the roof is laid are 30 feet long, including

anyanavicka [17]

Solution :

Given :

Span of the roof = 48 feet

Length of the rafter = 30 feet (including the 4 feet overhung)

So, for the 30 feet long rafter, 26 feet will be rafter length from the high point of the roof to the edge of the roof and 4 feet will be the roof overhung.

Therefore, the horizontal span per rafter is

$=\frac{48}{2}$

= 24 feet

a). So the rise of the roof is $= \sqrt{(26)^2-(24)^2}$

= 10 feet

b). Pinch of the roof is $=\frac{\text{rise}}{\text{run}}$

$=\frac{10}{24}$

$=\frac{5}{12}$

c). The percent of the roof used as overhung is

$=\frac{4+4}{60}\times 100$

$=\frac{80}{6}$

= 13.33 %

8 0

3 years ago

X+y=4 2x+y=5<br>solve this system graphically

kykrilka [37]

The first one is y=x+4 and the second one is y=-2x+5

3 0

4 years ago

Read 2 more answers

Two equations and their graphs are given. Find the intersection point(s) of the graphs by solving the system. X2 + y = 0 x3 − 12

Murljashka [212]

<h3>Given</h3>

x² +y = 0

x³ -12x -y = 0

the intersection point(s) (x, y)

<h3>Solution</h3>

Add the two equations together, then factor.

... (x² +y) + (x³ -12x -y) = 0 + 0

... x³ +x² -12x = 0

... x(x +4)(x -3) = 0

Then x = {0, -4, 3}.

The corresponding y-values are

... y = -x² = {0, -16, -9}

The points of intersection are (-4, -16), (0, 0), (3, -9)

8 0

3 years ago

Explain how an immune system response start after a macrophage attacks pathogen

Black_prince [1.1K]

By engulfing and digesting them

4 0

4 years ago

SURFACE AREAS – PYRAMIDS URGENT

soldier1979 [14.2K]

In this question , to find the total surface area , we have to find the area of all faces and add them .

And here the base is a hexagon. THe formula of area of hexagon is

$\frac{3 \sqrt 3}{2} a^2$

And in the given diagram, side length , a=4cm , so area is

$\frac{3 \sqrt 3}{2} (4)^2 = 24 \sqrt 3$

Now we need to find the area of triangle.

We have 6 triangular faces. And for area of triangle, we need the slant edge, and for that we use pythagorean formula

$8^2+(2 \sqrt 3)^2=h^2 \\ h^2 =76 \\ h = 2 \sqrt{19}$

Now we use the formula of area of triangle which is half times the product of base times height. And since there are 6 triangles, so we have to multiply by 6 too.

$=6*(1/2)*4*2 \sqrt{19} = 104.61$

So total surface area is

$24 \sqrt 3 + 104.61 =146.2 cm^2$

3 0

3 years ago