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Fudgin [204]
2 years ago
12

Complete the following tasks for this equation: b/7.8= -2.15.

Mathematics
1 answer:
riadik2000 [5.3K]2 years ago
8 0

Answer:

Step-by-step explanation:

Factors

  • A term in multiplication for an entire variety by which a bigger complete quantity may be divided
  • A divisor is an integer that evenly divides a range without leaving the rest
  • Factorization is the decomposition of an item right into a product of other objects
  • Integer factorization, the manner of breaking down a composite quantity into smaller non-trivial divisors
  • A coefficient, a multiplicative thing in an expression, usually more than a few
  • The act of forming a component institution or quotient ring in summary algebra
  • A von Neumann algebra, with a trivial center
  • Factor (graph principle), a spanning subgraph
  • Any finite contiguous sub-sequence of a word in a group concept

(b)/(7.8)=-2.15

Multiply each term in the equation by 7.8.

(b)/(7.8)*7.8=-2.15*7.8

Cancel the common factor of (1)/(7.8).

1b=-2.15*7.8

Multiply -2.15 by 7.8 to get -16.77.

1b=-16.77

Divide each term in the equation by 1.

(1b)/(1)=-(16.77)/(1)

Cancel the common factor of 1.

b=-(16.77)/(1)

Divide -16.77 by 1 to get -16.77.

b=-16.77

#SPJ10

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miles has 25 coins In his pocket. Some are Nichols and some are dimes. He has a total of $1.65 how many of each type of coin doe
Leni [432]

▪ Answer:

n = 17

d = 8

▪ Step-by-step explanation:

Hi there !

1 nickel = 5c

1 dime = 10c

$1.65 = 165c

n + d = 25 => n = 25 - d

5n + 10d = 165

replace n

5(25 - d) + 10d = 165

125 - 5d + 10d = 165

5d = 165 - 125

5d = 40

d = 8 (dimes)

n = 25 - d

n = 25 - 8

n = 17 (nickels)

Good luck !

7 0
3 years ago
HELP!
Advocard [28]

9)its a fraction

x=−451/19

y=−302/19



16)

Line 1: y = 5x +13

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7 0
4 years ago
Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?
cluponka [151]

Under the given transformation, the Jacobian and its determinant are

\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2

so that

\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv

where D' is the region D transformed into the u-v plane. The remaining integral is the twice the area of D'.

Now, the integral over D is

\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y

but through the given transformation, the boundary of D' is the set of equations,

\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}

We require that u>0, and the last equation tells us that we would also need v>0. This means 1\le v\le\sqrt2 and 0, so that the integral over D' is

\displaystyle2\iint_{D'}\mathrm du\,\mathrm dv=2\int_1^{\sqrt2}\int_0^{6v}\mathrm du\,\mathrm dv=\boxed6

4 0
3 years ago
The first five terms of a sequence are
Elena L [17]

Answer:

(a) 7 + 3( n - 1 )

(b) 1006

Step-by-step explanation:

ARITHMETIC SEQUENCE.

The number of term of an Arithmetic progression has the formular :

nth term = a + ( n - 1 ) d

a = 7

d = 10 - 7 = 3

nth term = 7 + ( n - 1 ) 3

= 7 + 3n - 3

= 7 + 3( n - 1 )

Therefore,

the nth term of the sequence

= 7 + 3( n - 1 )

(b) For the 1000th term

= 7 + 3 ( 1000-1 )

= 7 + ( 999 )

7 + 999 = 1006

Therefore,

the 1000th term = 1006

5 0
2 years ago
Expand in logarithmic expression
olchik [2.2K]
ln( \frac{m^{5}}{n^{2}})^{3} =3ln( \frac{m^{5}}{n^{2}})= 3(ln({m^{5})-ln({n^{2}))=3(5ln(m)-2ln(n) = 15*ln(m)-6*ln(n)



The answer is 15*ln(m)-6*ln(n)  
3 0
3 years ago
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