Given:
The sum of two terms of GP is 6 and that of first four terms is 
To find:
The sum of first six terms.
Solution:
We have,


Sum of first n terms of a GP is
...(i)
Putting n=2, we get


...(ii)
Putting n=4, we get



(Using (ii))
Divide both sides by 6.
Taking square root on both sides, we get

Case 1: If r is positive, then using (ii) we get
The sum of first 6 terms is




Case 2: If r is negative, then using (ii) we get
The sum of first 6 terms is




Therefore, the sum of the first six terms is 7.875.
Complete question:
A circle with radius 3 has a sector with a central angle of 1/9 pi radians
what is the area of the sector?
Answer:
The area of the sector =
square units
Step-by-step explanation:
To find the area of the sector of a circle, let's use the formula:

Where, A = area
r = radius = 3
Substituting values in the formula, we have:

The area of the sector =
square units
Idek how to do that omg but 3 is a triangles sides and wdym by “do”
Answer:
B.3x+8=66
Step-by-step explanation:
i think ito po Ang answer hehehe