Answer:
m+n=54 and m=3n+8 is the system of equations that could be used to determine the price of each book.
Step-by-step explanation:
Given,
Total cost of maths book and novel = $54
Let,
Cost of maths book = m
Cost of novel = n
According to given statement;
m+n=54 Eqn 1
the price of the math textbook, m, is $8 more than 3 times the price of the novel
m = 3n+8 Eqn 2
m+n=54 and m=3n+8 is the system of equations that could be used to determine the price of each book.
Step-by-step explanation:
Answer:
a) $15287.71
b) $15017.64
c) $16,368 − <em>r</em>%
Step-by-step explanation:
<u>Mary's car price (including tax): $16,368</u>
[<em>possible tax rates and listing prices</em>]
<u>a) 6.6%</u>
➠ $15287.71
<u>b) 8.25%</u>
➠ $15017.64
<u>c) </u><u><em>r</em></u><u> (any rate)</u>
➠ $16,368 − <em>r</em>%
<u>How did I find my answers?</u>
I had to <em>find the sales tax</em>, and<em> subtract it from the overall cost</em> of the item.
- To find the sales tax, all I had to do was multiply the sales tax percentage by the price of the item
- Next, all I had to do was subtract the sales tax from the item's cost
Under A straight line basis which is a method of computing depreciation and amortization by dividing the difference between an asset's cost and its expected salvage value by the number of years it is expected to be used. Also known as straight line depreciation or straight line amortization, this is the simplest depreciation method. But instead of that find The rate of depreciation
100/5 years=20% depreciation rate per year
Total cost 250×50=12,500
Salvage value 40×50=2,000
Subtract the salvage value from the total cost of televisions
12,500−2,000=10,500
In the first year the depreciation is
10,500×0.2=2,100
Book value
12,500−2,100=10,400
In the second year the depreciation is
10,500×0.2=2,100
Book value
10,400−2,100=8,300
In the third year the depreciation is
10500×0.2=2100
Book value
8300-2100=6200
the book value for all of the televisions at the end of the third year is 6200
65.5 divided by 2.5=26.2
answer is choice D
